Answer:
680g of mercury is the mass of the sample of mercury.
Explanation:
Density is an unit used to relates the mass of an object per unit of volume.
For example, in the problem, the density of mercury is 13.6g/cm³, as cm³ is equal to milliliters, mL, the density is: 13.6g/mL.
If you have 50.0mL of mercury, the mass is:
50.0mL * (13.6g / mL) =
<h3>680g of mercury is the mass of the sample of mercury.</h3>
You find the number of protons in an atom by looking at the periodic table.
1) Find your element.
2) Locate The atomic number of your element
3) The Atomic Number is also the number of protons.
Usually, the atomic number is on the on the top of the atomic symbol.
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Explanation:
if it was meant for [Ar]4s²3d¹ :
1s²2s²2p⁶3s²3p⁶4s²3d¹
number of e‐ : 21
atomic number is 21.. element is scandium
ion: Sc³+
Answer:
1.8 x 10⁻⁵
Explanation:
NH3(aq) + H2O(l) ⇄ NH4⁺(aq) + OH⁻(aq)
I 0.95 0 0
C -x +x +x
E 0.95-x x x
Kb= [NH₄⁺] [OH⁻] / ( NH₃) = x²/ (0.95-x )
P(OH) = 14-PH = 14-11.612 = 2.388
(OH)⁻¹ = 10⁻²°³⁸⁸ = 4.09 x 10⁻³ = x
Kb = (4.09 x 10⁻³)²/ (0.95-4.09 x 10⁻³)
= 1.8 x 10⁻⁵
Given what we know, we can confirm that option A is correct in that Stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter.
<h3>What are IMFs?</h3>
IMF is the acronym used to describe intermolecular forces. These forces include all of the forces that bind molecules together, of which water has plenty. This bonding force creates a high adhesion and thus gives water its surface tension which makes it stay together in the shape of a drop.
Therefore, we can confirm that stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter, and therefore that option A is correct.
To learn more about molecular forces visit:
brainly.com/question/25863653?referrer=searchResults