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sladkih [1.3K]
3 years ago
14

The PH solution of NH3 of 0.950molar solution is 11.612. find the Kb​

Chemistry
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

1.8 x 10⁻⁵

Explanation:

 NH3(aq)  +  H2O(l)  ⇄ NH4⁺(aq)  +   OH⁻(aq)

I  0.95                              0                    0

C -x                                 +x                  +x

E 0.95-x                           x                    x

Kb= [NH₄⁺] [OH⁻] / (  NH₃) = x²/ (0.95-x )

P(OH) = 14-PH = 14-11.612 = 2.388

(OH)⁻¹ = 10⁻²°³⁸⁸ = 4.09 x 10⁻³ = x

Kb = (4.09 x 10⁻³)²/ (0.95-4.09 x 10⁻³)

= 1.8 x 10⁻⁵

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Answer:

See explanation and image attached

Explanation:

The reaction of 1-bromo-2-tert-butylcyclohexane with  potassium tert-butoxide is an elimination reaction that occurs by E2 mechanism.

The E2 reaction proceeds faster when the hydrogens are in an antiperiplanar position at an angle of 180 degrees.

This is only attainable in the trans isomer of 1-bromo-2-tert-butylcyclohexane. Hence trans 1-bromo-2-tert-butylcyclohexane reacts faster with potassium tert-butoxide

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D. Hydrogen bonds between complementary base pairs89

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Differentbetween sound and vibration​
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A bomb calorimeter has a heat capacity of 783 J/oC and contains 254 g of water whose specific heat capacity is 4.184 J/goC. How
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Answer : The amount of heat evolved by a reaction is, 4.81 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

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c_1 = specific heat of calorimeter = 783J/^oC

c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = 254 g

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Now put all the given values in the above formula, we get:

q=[(783J/^oC\times -2.28^oC)+(254g\times 4.184J/g^oC\times -2.28^oC)]

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Therefore, the amount of heat evolved by a reaction is, 4.81 kJ

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3 years ago
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