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Sauron [17]
3 years ago
11

Simplifying Rational Expressions Image below

Mathematics
1 answer:
BigorU [14]3 years ago
4 0
Tl;dr with exponents like this is that negative signs are bad, get rid of them.

You can write this as:
( \frac{1}{4ab})^{-1})^{^2}
Anything to the -1 involves flipping the fraction, so we now simplify this to:

( \frac{4ab}{1}) ^2=(4ab)^2

Now we know with exponents outside of the bracket, it's the same as writing the bracket out twice, which means everything is multiplied by everything, i.e. in this case we multiply 4ab by 4ab which means we square everything.

Therefore
(4ab)^2=4^2a^2b^2 \\  \\ \boxed{=16a^2b^2} 

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Lines a, b, c, and d Intersect as shown.
Mnenie [13.5K]

Answer:

95 is the answer I took the test

8 0
3 years ago
Abby owns a comic book that originally sold for 12¢ in 1969. In 2014, the comic book had an appraised valued of $3,700. Given th
Trava [24]

Hi,

Answer: B) 25.82%

<u>My work:</u> For this problem you can easily achieve this problem (Preferably with a caculator) by taking the date’s 2014 and 1969 the time of growth and subtract them. When you do this you get the answer 45. From there you you take 45 (With caculator) and multiply it with 25.82 % (To do this you take 25.82 and press 2nd, then the percent). When you do this you get 11.619 which rounded is 12; furthermore, which is your answer.

I Hope I Helped!

3 0
4 years ago
Order these from greatest to least: 1/8; 0.14; 1/5; 13%
Rasek [7]
1/5, 0.14, 13%, 1/8, it requires me to have more characters in the answer...
3 0
3 years ago
A train traveling at a constant speed takes a passenger from Elm to Millwood, stopping at Centre along the way. It takes 2004-01
ZanzabumX [31]
The complete problem is as following:
A train traveling at a constant speed takes a passenger from Elm to Millwood, stopping at Centre along the way. It takes 5 times as long to go from Centre to Millwood as it does to go from Elm to Centre. The entire trip is 48 miles. How far is the ride from Centre to Millwood? Name a geometric postulate or theorem used to find the solution. 
A) 8 miles ; segment addition postulate 
B) 8 miles; segment bisector theorem 
C) 40 miles; segment addition postulate 
D) 40 miles; segment bisector theorem
=======================================================
Solution ;
Let the time taken from Elm to Centre = x  ⇒⇒⇒ segment (1)

∴ the time taken from Centre to Millwood = 5x  ⇒⇒⇒ segment (2)

∴ Total time of all the trip = x + 5x = 6x
The entire trip is 48 miles and the train traveling with constant speed
∴ speed = distance over the time = \frac{48}{6x} =  \frac{8}{x}
So, the distance from Centre to Millwood = speed * time = \frac{8}{x} * 5x = \framebox{40 \ miles}
As seen in the answer, we have added the segment (1) to segment (2)
So, The geometric postulate used to find the solution is segment addition postulate

So, the correct option is C) 40 miles; segment addition postulate

=======================================================
Another solution :
From Elm to Centre = x ⇒⇒⇒ segment (1)
From Centre to Millwood = 5x ⇒⇒⇒ segment (2)
∵ The train traveling with constant speed 
∴ Distance is proportional with the time
By using the ratio and proportional as following 

Segment (1) : segment (2) : Total \\ \ \ &#10;. \ \ \ \ \ \ \  x \ \ \ \  \ \  :  \ \ \ \ \ 5x \ \ \ \ \ \ \ : \ \ 6x \\&#10;. \ \ \ \ \ \ \  ? \ \ \ \  \ \  :  \ \ \ \ \ \ \ ? \ \ \ \ \ \ \ \ : \ \ \ 48

∴ segment (2) = \frac{48 * 5x}{6x} = \framebox {40 miles}&#10;

we have used the postulate of segment addition to add x and 5x.

So, the correct option is C) 40 miles; segment addition postulate
4 0
4 years ago
Combine like terms 4a2-3b2+ 4b + 10a2
jolli1 [7]

Answer:

14a² - 3b² + 4b

Step-by-step explanation:

Like terms are the terms that have similar stuff on it, like same variables, no variables, and stuff like that.

4a2-3b2+ 4b + 10a2

4a² and 10a² is similar. 4a² + 10a² = 14a²

Now, the equation is 14a² - 3b² + 4b. There is no more like terms left, so that is the answer.

Hope this helps!!

-Ketifa

4 0
3 years ago
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