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Ahat [919]
3 years ago
10

Y=-3x+2 convert slope intercept form

Mathematics
1 answer:
marissa [1.9K]3 years ago
5 0

Answer:

Its already in slope intercept form

Step-by-step explanation:

y=mx+b

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Can anyone help me solve this?
schepotkina [342]

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the answer is

<em>n</em><em>=</em><em>5</em>

SANA MAKATULONG

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PLZ HELP!!!<br> what r the answers??
vekshin1

Answer:

Question 2 the answer is C) y = -3/2x + 2

Question 3 the answer is D) x = 4

Step-by-step explanation:

To solve either we first need to know that parallel lines have the same slope.

So in #2 we know that the new line will also have a slope of -3/2. Therefore, we can use that along with the point given in the problem in point-slope form to get the new equation.

y - y1 = m(x - x1)

y + 1 = -3/2(x - 2)

y + 1 = -3/2x + 3

y = -3/2x + 2

And for #3, we know that we have a vertical line due to the fact that it is expressed as x = a number. Therefore, we must have the same in the answer. D is the only one that has such an answer.

3 0
3 years ago
F(x) = 4x^2 - 3x + 2kx + 1 
dybincka [34]
f(x)=4x^2-3x+2kx+1=4x^2+(2k-3)x+1\\\\a=4;\ b=2k-3;\ c=1\\\\function\ has\ two\ zeros\ when\ \Delta=b^2-4ac > 0\\\\\Delta=(2k-3)^2-4\cdot4\cdot1=4k^2-12k+9-16=4k^2-12k-7 > 0\\\\a_k=4;\ b_k=-12;\ c_k=-7\\\\\Delta_k=(-12)^2-4\cdot4\cdot(-7)=144+112=256\\\\k_1=\frac{-b_k-\sqrt{\Delta_k}}{2a_k};\ k_2=\frac{-b_k+\sqrt{\Delta_k}}{2a_k}

\sqrt{\Delta_k}=\sqrt{256}=16\\\\k_1=\frac{12-16}{2\cdot4}=\frac{-4}{8}=-\frac{1}{2};\ k_2=\frac{12+16}{2\cdot4}=\frac{28}{8}=\frac{7}{2}\\\\a_k=4 > 0\ (up\ parabola\ arms-see\ the\ picture)\\\\Answer:k\in(-\infty;-\frac{1}{2})\ \cup\ (\frac{7}{2};\ \infty)

6 0
3 years ago
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