Answer: 500 people
Step-by-step explanation:
Let there are x people in the survey.
According to the question,
People who like football as their favorite sports = 42 % of x = 0.42 x
People who like baseball as their favorite sports = 33 % of x = 0.33 x
People who like soccer as their favorite sports = 25 % of x = 0.25 x
But, 210 people said football was their favorite sport.
⇒ 0.42 x = 210
⇒ 42 x = 21000
⇒ x = 500
Therefore, there are 500 people in the survey.
Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
The mean and the standard deviation are given, respectively, by:
.
The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:
X = 790:
Z = 1.8
Z = 1.8 has a p-value of 0.9641.
X = 575:
Z = -2.5
Z = -2.5 has a p-value of 0.0062.
0.9641 - 0.0062 = 0.9579.
0.9579 = 95.79% probability of a month having a PCE between $575 and $790.
More can be learned about the normal distribution at brainly.com/question/4079902
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