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Sholpan [36]
3 years ago
10

How do I do it ?skskskksksk help

Mathematics
1 answer:
ivanzaharov [21]3 years ago
8 0

Answer:

lol you deleted my answer loser

Step-by-step explanation:

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What is the answer to this question above?
djyliett [7]

Answer:

is it multiple choice

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A bag of marbles consists of 14 blue marbles and 7 red marbles. If you reach into the bag and choose 2 marbles,
julsineya [31]

Answer:

chances are 10.5

Step-by-step explanation:

8 0
2 years ago
Determine the slope and y intercept of the graph of the equation.
iren [92.7K]
1. Slope = -7
Y intercept= 8
7 0
2 years ago
Twice as many students are in the chess club as in the fencing club.The number of students in the fencing club is one fifth the
jekas [21]

Answer:

28 students

Step-by-step explanation:

Let number of students in cooking club = x

Number of students in fencing club = 1/5 x

Number of students in chess club = 2(1/5)x

Since, There are 42 more students in the cooking club than in the chess club

Then ;

Number of students in chess club = Number of students in cooking club - 42

2(1/5)x = x - 42

(2/5)x - x = - 42

(2/5)x - x = - 42

-0.6x = - 42

x = 42 / 0.6

x = 70

Hence, number of students in chess club :

(2/5) * 70 = 28

4 0
2 years ago
A family wants to save for college tuition for their daughter. What continuous yearly interest rate r% is needed in their saving
sergey [27]

Answer:

The continuous yearly interest is  22.5% per year.

Step-by-step explanation:

Continuous yearly interest:

Continuous yearly interest is defined as the sum of the interest comes from principle and the interest comes from interest.

The formula for continuous interest yearly is

A=Pe^{rt}

where A = The final amount =$110,000

P= principle =$4,700

r= rate of interest

t= time (in year)= 14 years

\therefore 110,000= 4,700e^{r\times 14}

\Rightarrow e^{14r}= \frac{110,000}{4,700}

Taking ln both sides

\Rightarrow ln e^{14r}= ln(\frac{110,000}{4,700})

\Rightarrow {14r}= ln(\frac{1100}{47})

\Rightarrow r=\frac{ln( \frac{1100}{47})}{14}

\Rightarrow r = 0.225  (approx)

The continuous yearly interest is 0.225 = 22.5% per year.

4 0
3 years ago
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