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Sholpan [36]
3 years ago
10

How do I do it ?skskskksksk help

Mathematics
1 answer:
ivanzaharov [21]3 years ago
8 0

Answer:

lol you deleted my answer loser

Step-by-step explanation:

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Rewrite as a simplified fraction.<br> \large{2.1\overline{6} = ?}2.1 <br> 6<br> =?
slamgirl [31]

Answer:

Note that

0.16666...is equivalent to 1/6

Step-by-step explanation:

We can use the sum of fractions to write out the decimal:

For this particular question, we can see that

0.16666...is the fraction 1/6, therefore

the given decimal

2.16666...=2+1/6=13/6

6 0
3 years ago
Mr.James has a cylindrical beakers that measure 4 inches in diameter and are 9 inches high .What is the volume contained within
Ksju [112]

Cylinder Volume = PI * radius^2 * height


Cylinder Volume = 3.14 * 2^2 * 9


Cylinder Volume = 113.04 cubic inches


1728.com/diamform.htm



8 0
3 years ago
Read 2 more answers
What is the sum of natural numbers less than 200 neither divisible by 3 nor by 5
Sveta_85 [38]

Step-by-step explanation:

The required sum 

=(1+2+3+...+199)−(3+6+9+...+198)−(5+10+15+...+195)+(15+30+45+...+195)

=2199(1+199)−266(3+198)−239(5+195)+213(15+195)

 

=199×100−33×201−39×100+13×105=10732

8 0
3 years ago
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If a+b+c=0 then find the value of a^2+b^2+c^2/a^2-bc pls help me
VladimirAG [237]

a+b+c=0

[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]

[a^2+b^2+c^2+2ab+2ac+2bc=0]

[a^2+b^2+c^2=-(2ab+2ac+2bc)]

[a^2+b^2+c^2=-2(ab+ac+bc)] (i)

also

[a=-b-c]

[a^2=-ab-ac] (ii)

[-c=a+b]

[-bc=ab+b^2] (iii)

adding (ii) and (iii) ,we have

[a^2-bc=b^2-ac] (iv)

devide (i) by (iv)

[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
8 0
3 years ago
What is the midpoint of the segment below?
Veronika [31]
I am pretty sure it is B.
3 0
3 years ago
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