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Gwar [14]
3 years ago
15

For which fraction pairs would it be useful to use the benchmarks 0, One-half, and 1 to compare? Check all that apply.

Mathematics
1 answer:
koban [17]3 years ago
8 0

Answer:

,

Step-by-step explanation:

thank my answer

pls mark brilinias

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Which decribes how you beed to pay a charged card bill
dusya [7]
That depends. what are the answer choices?
5 0
3 years ago
2(a-3)÷(a-4)(a-5)+a-1÷(3-a)(a-4)+a-2÷(5-a)(a-3) simplify.​
Arlecino [84]

<u><em>I'm almost confident that I did this wrong, but i tried...</em></u>

Answer:

4a-9 ÷ -19

Step-by-step explanation:

(It was easier for me to put it in fractions)

\frac{2(a-3)}{(a-4)(a-5)} + \frac{a-1}{(3-a)(a-4)} + \frac{a-2}{(5-a)(a-3)}        (3-a) (a-4) + (5-a) (a-3)

\frac{2a-6}{(a-4)(a-5)} + \frac{a-1}{(3-a)(a-4)} +  \frac{a-2}{(5-a)(a-3)}      3 - a · a - 4 + 5 - a · a - 3

    \frac{2a-6}{(2a-20)} + \frac{a-1}{(3-a)(a-4)} + \frac{a-2}{(5-a)(a-3)}               3 - a + 1 - a - 3

   \frac{2a-6+a-1+a-2}{(2a-20)+(3-a)(a-4)+(5-a)(a-3)}                        1 - a - a

                 \frac{4a-9}{2a-20+1-2a}                                       1 - 2a

                   \frac{4a-9}{2a-19-2a}

                      \frac{4a-9}{-19}

8 0
3 years ago
Find the distance between two points. ENTER THE NUMBER THAT GOES BENEATH THE RADICAL SYMBOL.
iVinArrow [24]
<h2>The distance between two points is \sqrt{98} or 9.9 units</h2>

<em><u>Solution:</u></em>

<em><u>The distance between two points is given as:</u></em>

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}

From given,

(x_1, x_2) = (-5, 5)\\\\(x_2, y_2) = (2, -2)

<em><u>Substituting the values we get,</u></em>

d = \sqrt{(2+5)^2+(-2-5)^2}\\\\d = \sqrt{7^2+(-7)^2}\\\\d = \sqrt{49+49}\\\\d = \sqrt{98}\\\\d = 9.899 \approx 9.9

Thus the distance between two points is \sqrt{98} or 9.9 units

8 0
3 years ago
A lot of 9 components contains 3 that are defective. Two components are drawn at random and tested. Let be the event that the fi
kirza4 [7]

Answer:

Probabilty of first component drawn defective= 0.1161

Probability of second component drawn defective= 0.1560

Step-by-step explanation:

Total component = 9

Defective component= 3

Non-defective component= 6

Probability of defective= 3/9

= 0.3333

Probabilty of non defective= 1-0.3333

= 0.6666

Probabilty of first component drawn is defective

= 9C1(0.333)¹(0.6666)^8

= 9(0.3333)(0.0387)

= 0.1161

Probabilty of second component is defective

= 8C1(0.3333)¹(0.6666)^7

= 8(0.3333)(0.0585)

= 0.1560

7 0
3 years ago
I need help answering this!!! I just need help on how to do it or fragments of an answer. If you give me the straight-up answer
Marizza181 [45]
First part 3x+(-5)=19 you need to remove parenthesis move the constant -5 to the right to have 3x=19+5 then add those to get 3x=24 then divide to get x=8
8 0
3 years ago
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