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Allushta [10]
4 years ago
5

How do you work this problem? 5 4/10 + 3 6/9

Mathematics
1 answer:
oee [108]4 years ago
3 0

Answer:

136/15

Step-by-step explanation:

5 4/10+3 6/9

=54/10+33/9

=9*54+10*33/90

=486+330/90

=816/90

=136/15

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2 years ago
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An object is thrown upward at a speed of 124 feet per second by a machine from a height of 19 feet off the ground. The height h
klasskru [66]

a) For this question we set h=59 and solve for t, in order to do so we use the general formula for second-degree equations:

\begin{gathered} t=\frac{-124\pm\sqrt[]{124^2-4(-16)(-40)}}{2(-16)} \\ t=\frac{-124\pm113.21}{-32} \end{gathered}

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b) When the object reaches the ground, h=0 therefore:

0=-16t^{2}+124t+19

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\begin{gathered} t=\frac{-124\pm\sqrt[]{124^2-4(-16)(19)}}{2(-16)} \\ t=\frac{-124\pm\sqrt[]{16592}}{-32}=\frac{-124\pm128.81}{-32} \end{gathered}

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7 0
1 year ago
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