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Allushta [10]
3 years ago
5

How do you work this problem? 5 4/10 + 3 6/9

Mathematics
1 answer:
oee [108]3 years ago
3 0

Answer:

136/15

Step-by-step explanation:

5 4/10+3 6/9

=54/10+33/9

=9*54+10*33/90

=486+330/90

=816/90

=136/15

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Explain in words,how to find the product of -4(-1.5) using a number line. Where do you end up?
Gemiola [76]

Answer:

so u multiply negative four times nagative 1.5

6 0
3 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.<br> |x = °|
Serga [27]
X+30+70=180
x+100=180. -100 both sides
x=80

|x=80° |
8 0
3 years ago
A college is currently accepting students that are both in-state and out-of-state. They plan to accept three times as many in-st
ziro4ka [17]

Answer:

0 < x ≤ 100 and 0 < y ≤ 300

Step-by-step explanation:

THIS IS THE COMPLETE QUESTION BELOW;

college is currently accepting students that are both in-state and out-of-state. They plan to accept three times as many in-state students as out-of-state, and they only have space to accept 100 out-of-state students. Let x = the number of out-of-state students and y = the number in-state students. Write the constraints to represent the incoming students at the college.

0 < x ≤ 100 and 0 < y ≤ 300

x > 0 and y > 0

0 < x ≤ 100 and y > 300

0 < x and y < 100

SOLUTION

they only have space to accept 100 out-of-state students,which means that the Maximum number of out-of-state students that can be accepted is 100

Then x= 100(Maximum number of out-of-state students that can be accepted)

They plan to accept three times as many in-state students as out-of-state which means that

Y = 3x(Maximum number of in-state students)

Then we can deduced that the numbee out-of-state students that can be accepted can lyes between the range of 0 and 100 which means from interval 0 to 100

Which can be written as 0 < x ≤ 100

But we need to know the interval for the Maximum number of in-state students(Y), to do that we need to multiply the equation above by 3 since Y = 3x

0 < x ≤ 100

3× 0 = 0

3× X = X

3× 100= 300

Then 0 < 3x≤ 300

But we know that Y = 3x then substitute into last equation

We have

0 < y ≤ 300

ThenBthe constraints to represent the incoming students at the college is

0 < x ≤ 100 and 0 < y ≤ 300

8 0
3 years ago
Write one hundred twenty-three and fourteen thousandths as a decimal number.
DochEvi [55]

Answer:

.12314

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please help me only say something if you really know the answer
Diano4ka-milaya [45]

Answer:

B

Step-by-step explanation:

Starting with 7,000, after 0 years there will be no increase so you still have 7,000.

The fist year you increase by 5% of 7,000.

.05x7000=350

You have a 350 increase, add that to the original 7000 to find the actual population after 1 year (domain value 1).

After 1 year: 7350

For year 2 there is an increase of 5% again, only this time we find 5% of 7350 since that was the previous years population.

.05x7350=368

Add that to previous population.

368+7350=7718

At this point so far the yearly populations have been (7000, 7350, 7718)

Answer choice B is the only one to have this progression.

3 0
3 years ago
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