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3 years ago

What are the co-ordinance of point Q

Mathematics

1 answer:

dimulka [17.4K]3 years ago

3 0

Answer:

<em>(6,3), last option</em>

Step-by-step explanation:

<u>Symmetry To A vertical line</u>

If the point Q (unknown) is symmetric to point P(2,3) with respect to x=4, it means it's located at the same distance to the line as P while keeping the same y-coordinate.

The point P has a distance of 4-2=2 units with respect to x=4. Q must have its x coordinate equal to 4+2=6, and keeping the y-coordinate equal to 3

The coordinates of Q are (6,3), last option

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3 years ago

A2-b2 ÷5a-5b factorise

katrin2010 [14]

Answer:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "b2" was replaced by "b^2". 1 more similar replacement(s).

STEP

5a + 5b

Simplify ———————

a2 - b2

STEP

Pulling out like terms

2.1 Pull out like factors :

5a + 5b = 5 • (a + b)

Trying to factor as a Difference of Squares:

2.2 Factoring: a2 - b2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : a2 is the square of a1

Check : b2 is the square of b1

Factorization is : (a + b) • (a - b)

Canceling Out :

2.3 Cancel out (a + b) which appears on both sides of the fraction line.

Final result :

5 / a -b

Step-by-step explanation:

3 0

3 years ago

Prove that the curve a(t) = (cost, sin 2t, cos 2t) is regular on R and that it self-intersects at (1,0,1). Check the self-inters

alexandr402 [8]

Answer:

The function a (t) is a vector function composed of the component functions $a_ {1} (t) = cost, a_ {2} (t) = sin2t$ and $a_ {3} (t) = cos2t$ . How $a_ {1} (t), a_ {2} (t), a_ {3} (t)$ are infinitely derivable functions in R, so they are regular functions in R.

Now, for $t = 0$ , you have to $a (0) = (cos (0), sin2 (0), cos2 (0)) = (1, 0, 1)$ . How the functions $a_ {1} (t), a_ {2} (t), a_ {3} (t)$ are periodic functions with period $2 \pi,$ the vector function $a (t)$ will take the same point $(1, 0 , 1)$ at $t = 2n\pi, n = 0, 1, 2, 3, ...$ then the vector function is auto-intercepted