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ivolga24 [154]
3 years ago
9

If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?

Mathematics
1 answer:
Inessa05 [86]3 years ago
5 0

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

g(x)=4x^2-16

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:

\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)

Therefore, If we shift the red graph 9 units to the right and 1 down, our new function (let's call it h(x)) will be:

h(x)=4\left(x-9\right)^{2}-16-1 \\ \\ Simplifying: \\ \\ h(x)=4\left(x-9\right)^{2}-17

This graph is the blue graph below. Let's verify the transformation taking the vertex of the red graph:

(0,-16)

By translating the 9 units to the right and 1 down the vertex is also translated by the same rule, so:

New \ vertex: \\ \\ (0+9,-16-1) \\ \\ (9,-17)

<h2>Learn more:</h2>

Cubic function: brainly.com/question/13773618#

#LearnWithBrainly

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kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

V = L^{3}

Donde:

L - Longitud de la arista, medida en dados.

V - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

L = \sqrt[3]{V}

Dado que V = 125\,dados^{3}, encontramos que la altura del cubo de mayor tamaño sería:

L =\sqrt[3]{125\,dados^{3}}

L = 5\,dados

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

A = L^{2}

Donde:

L - Longitud de arista, medida en dados.

A - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de L tal que no supere 125 y de un área entera. Es decir:

L \leq 125\,dados

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

L^{2}< 125\,dados^{2}

Esto nos lleva a decir que:

L < 11.180\,dados

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

n = (11\,dados)^{2}

n = 121\,dados

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

4 0
3 years ago
Need help , if you can answer it pls do . thank you
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Answer:

9

Step-by-step explanation:

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hope this helped

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Answer:

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Rebecca has 12 photos she wants to hang side by side on her wall.A. If she only wants to display 8 of the photos, in how many wa
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A.

If she will choose 8 from 12 photos, the total number of ways she can choose is given by a combination of 12 choose 8, since the order of the photos doesn't matter.

The formula for a combination of n choose p is:

C(n,p)=\frac{n!}{p!(n-p)!}

For n = 12 and p = 8, we have:

C(12,8)=\frac{12!}{8!(12-8)!_{}}=\frac{12\cdot11\cdot10\cdot9\cdot8!}{8!\cdot4!}=\frac{12\cdot11\cdot10\cdot9}{4\cdot3\cdot2}=495

So there are 495 ways.

B.

If she wants to arrange the 12 photos, the total number of ways is given by the factorial of 12:

12!=12\cdot11\cdot10\cdot9\cdot8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2=479001600

There are 479,001,600 ways.

C.

Since 10 photos already have specific places, we need to calculate the number of ways to arrange the other two photos in the two remaining places.

In this case, there are only 2 ways of organizing the remaining two photos:

Photo 1 first, photo 2 last, or photo 1 last and photo 2 first.

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