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tatuchka [14]
3 years ago
11

Solve x<3 and x≥−1 and write the solution in interval notation. If there is no solution, type ∅ .

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0

Shown in the Figure below

Step-by-step explanation:

In this exercise, we have the following system of inequalities:

x

The word and means intersection, so both inequalities must be true at the same time. We can graph this system as indicated in the figure below. Indeed, there is intersection between -1 and 1. Also, the number -1 is included in the solution because x\geq -1 and this is represented by the closed circle. On the other hand, the number 3 is not included in the solution because x and this is represented by the open circle.

<h2>Learn more:</h2>

Inequalities: brainly.com/question/12261425

#LearnWithBrainly

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Answer:

True!

Step-by-step explanation:

3(10) - 9

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Find the equation of the linear function represented by the table below in slope-intercept form.
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Find the midpoint of A and B where A has coordinates (2, 4)<br> and B has coordinates (-3, -9).
tatuchka [14]

Answer:

(-0.5,-2.5)

Step-by-step explanation:

  • (x1 + x2) / 2 = x midpoint
  • (y1 + y2) / 2 = y midpoint
<h3>X:</h3>

⇒ 2 + -3 = 5

⇒ 5 / 2 = -0.5

<h3>Y:</h3>

⇒ 4 + -9 = -5

⇒ -5 / 2 = -2.5

→ = (-0.5, -2.5)

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f(x) = 3 cos(x) 0 ≤ x ≤ 3π/4 evaluate the Riemann sum with n = 6, taking the sample points to be left endpoints. (Round your ans
Kruka [31]

Answer:

\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558

Step-by-step explanation:

We want to find the Riemann sum for \int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx with n = 6, using left endpoints.

The Left Riemann Sum uses the left endpoints of a sub-interval:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)

where \Delta{x}=\frac{b-a}{n}.

Step 1: Find \Delta{x}

We have that a=0, b=\frac{3\pi }{4}, n=6

Therefore, \Delta{x}=\frac{\frac{3 \pi}{4}-0}{6}=\frac{\pi}{8}

Step 2: Divide the interval \left[0,\frac{3 \pi}{4}\right] into n = 6 sub-intervals of length \Delta{x}=\frac{\pi}{8}

a=\left[0, \frac{\pi}{8}\right], \left[\frac{\pi}{8}, \frac{\pi}{4}\right], \left[\frac{\pi}{4}, \frac{3 \pi}{8}\right], \left[\frac{3 \pi}{8}, \frac{\pi}{2}\right], \left[\frac{\pi}{2}, \frac{5 \pi}{8}\right], \left[\frac{5 \pi}{8}, \frac{3 \pi}{4}\right]=b

Step 3: Evaluate the function at the left endpoints

f\left(x_{0}\right)=f(a)=f\left(0\right)=3=3

f\left(x_{1}\right)=f\left(\frac{\pi}{8}\right)=3 \sqrt{\frac{\sqrt{2}}{4} + \frac{1}{2}}=2.77163859753386

f\left(x_{2}\right)=f\left(\frac{\pi}{4}\right)=\frac{3 \sqrt{2}}{2}=2.12132034355964

f\left(x_{3}\right)=f\left(\frac{3 \pi}{8}\right)=3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=1.14805029709527

f\left(x_{4}\right)=f\left(\frac{\pi}{2}\right)=0=0

f\left(x_{5}\right)=f\left(\frac{5 \pi}{8}\right)=- 3 \sqrt{\frac{1}{2} - \frac{\sqrt{2}}{4}}=-1.14805029709527

Step 4: Apply the Left Riemann Sum formula

\frac{\pi}{8}(3+2.77163859753386+2.12132034355964+1.14805029709527+0-1.14805029709527)=3.09955772805315

\int_{0}^{\frac{3 \pi}{4}}3 \cos{\left(x \right)}\ dx\approx 3.099558

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Answer:

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