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sveticcg [70]
3 years ago
14

What is the equation of the midline of the function f(x) = 5.6sin (2.6x - 4.2) - 9.1?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
5 0

Answer:

f(x) = -9.1

Step-by-step explanation:

The midline is set on f(x) = -9.1, when the sine function is equal to zero, eliminating the effect from amplitude. The midline is a horizontal line. Hence, the equation of the midline is:

f(x) = -9.1

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\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS
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Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

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The cross product is

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\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi
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