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3 years ago

Poop x poop = diareha

Mathematics

2 answers:

eduard3 years ago

5 0

Answer:

You're correct

Step-by-step explanation:

Good answer!!

Genrish500 [490]3 years ago

3 0

Answer:

right

Step-by-step explanation:

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Y-5=1/16(x-3)^2 i dont understand how to solve this

VLD [36.1K]

Answer:

Step-by-step explanation:

Add 5 to both sides of the equation.

y=1/16⋅(x−3)2+5

Simplify each term.

y=(x−3)^2/16+5

Use the vertex form, y=a(x−h)2+k, to determine the values of a, h, and k. a=1/16 h =3 k=5

Since the value of a is positive, the parabola opens up.

Opens Up

Find the vertex (h,k).(3,5)

Find p, the distance from the vertex to the focus.

Find the focus.

(3,9)

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

x=3

3 0

4 years ago

Russell bought two rolls of tape. The first roll had 4.39 meters of tape and the second roll had 6.13 meters of tape. How many m

jarptica [38.1K]

The answer is 10.52 meters

4.39+6.13=10.52

hope this helps !

7 0

3 years ago

What is the feed conversion ratio of the chicken if its 34 days average weight is 1.9 kg and the total feed intake is 2.7 kg.?

DiKsa [7]

The feed conversion ratio is defined as the ratio of the total feed intake to the average weight of the animal.

The formula is given as:

Total feed intake(kg) / Average weight (kg)

Total feed intake = 2.7kg

Average weight = 1.9 kg

Hence,

Feed Conversion Ratio = 2.7kg/1.9kg

= 1.421

The correct option is a

To learn more, visit the link below:

brainly.com/question/13423712

3 0

3 years ago

Please someone help me with the question

Yuki888 [10]

Answer:

$\displaystyle \frac{d}{dx}[e^{2x}] = 2e^{2x}$

$\displaystyle \frac{d}{dx}[e^{3x}] = 3e^{3x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients
Exponential Rule [Multiplying]: $\displaystyle b^m \cdot b^n = b^{m + n}$

Calculus

Derivatives

Derivative Notation

eˣ Derivative: $\displaystyle \frac{d}{dx}[e^x] = e^x$

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[e^x \cdot e^x]$

$\displaystyle \frac{d}{dx}[e^{3x}] = \frac{d}{dx}[e^x \cdot e^{2x}]$

Step 2: Differentiate

$\displaystyle \frac{d}{dx}[e^{2x}]$

[Derivative] Product Rule: $\displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[e^x]e^x + e^x\frac{d}{dx}[e^x]$
[Derivative] eˣ Derivative: $\displaystyle \frac{d}{dx}[e^{2x}] = e^x \cdot e^x + e^x \cdot e^x$
[Derivative] Multiply [Exponential Rule - Multiplying]: $\displaystyle \frac{d}{dx}[e^{2x}] = e^{2x} + e^{2x}$
[Derivative] Combine like terms [Addition]: $\displaystyle \frac{d}{dx}[e^{2x}] = 2e^{2x}$

$\displaystyle \frac{d}{dx}[e^{3x}]$

[Derivative] Product Rule: $\displaystyle \frac{d}{dx}[e^{3x}] = \frac{d}{dx}[e^x]e^{2x} + e^x\frac{d}{dx}[e^{2x}]$
[Derivative] eˣ Derivatives: $\displaystyle \frac{d}{dx}[e^{3x}] = e^x(e^{2x}) + e^x(2e^{2x})$
[Derivative] Multiply [Exponential Rule - Multiplying]: $\displaystyle \frac{d}{dx}[e^{3x}] = e^{3x} + 2e^{3x}$
[Derivative] Combine like terms [Addition]: $\displaystyle \frac{d}{dx}[e^{3x}] = 3e^{3x}$