Ask question

Ask question

All categories

3 years ago

10

describe what is meant by "a constant change of direction".Identify whether the examples provided show a constant change of dire

ction when moving

1 answer:

liraira [26]3 years ago

7 0

"Constant change of direction" simply means on a curve.

The examples provided don't show a durn thing.

You might be interested in

What do Babys Come From

arlik [135]

Answer:

Mother

Explanation:

Is this actual question

5 0

4 years ago

A system has two possible energy states, E0 and E1 (with E1 > E0). If the difference between these energy states grows (E0 an

Ugo [173]

Answer:

The number of particles in state E0 over the number of particles in state E1 will reduce

Explanation:

E0 represents the ground level state when all the particles have same energy level.

E1 represents excited state in which only a few particle reaches

E0 and E1 get further apart means that the energy difference between the two level increases.

Thus, the number of particles in state E0 over the number of particles in state E1 will reduce.

5 0

3 years ago

Juan rides his horse with a constant<br> speed of 18 km/h. How far can he travel<br> in 1/2 hour?

Brut [27]

Answer:

He traveled 9km

Explanation:

To do this problem you need to use the equation which is Speed= distance/time and this problem gives you the speed which is 18 km/h and it gives you the time 1/2 hour so you write the equation 18= d/ 1/2 which his distance is 9km

3 0

3 years ago

mike's car can accelrate from 0 mph to 40 mph in 5 sec. what is the acceleration of his car miles per hour per sec?

siniylev [52]

1. 40-0=40

3. 40/5=8

8 ml/s

you find the range of acceleration(step one)

divide by the time(step two)

6 0

3 years ago

Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th

DiKsa [7]

Answer:

a. $\rm -1.49\ m/s^2.$

b. $\rm 50.49\ m.$

Explanation:

<u>Given:</u>

Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

<h2>(a):</h2>

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

$\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).$

At time t = 3 seconds,

$\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.$

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

<h2>(b):</h2>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

$\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.$

For the time interval of 2 seconds,

$\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt$

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

$\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.$

It is the displacement of the particle in 2 seconds.

7 0

4 years ago