Answer:
false
Explanation:
if an object is accelerating the object will not travel the same distance every time interval
The velocity of the block leaving the spring is determined as 18.26 m/s.
<h3>
Velocity of the block</h3>
The velocity of the block leaving the spring is calculated from the principle of conservation of energy.
K.E = Ux
¹/₂mv² = ¹/₂kx²
v² = kx²/m
v² = (500 x 2²)/6
v² = 333.33
v = √333.33
v = 18.26 m/s
Thus, the velocity of the block leaving the spring is determined as 18.26 m/s.
Learn more about velocity here: brainly.com/question/4931057
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Answer:
6.0 m/s²(5 s) = 30 m/s
Explanation:
Distance traveled in 15 s is
½(6.0)5² + 6.0(5)(10) = 375 m
Answer:
The answere is A force that pulls objects toward the center of Earth
Explanation:
Hope this helpe! :)
Answer:
0.1 s
Explanation:
The net force on the log is F - f = ma where F = force due to winch = 2850 N, f = kinetic frictional force = μmg where μ = coefficient of kinetic friction between log and ground = 0.45, m = mass of log = 300 kg and g = acceleration due to gravity = 9.8 m/s² and a = acceleration of log
So F - f = ma
F - μmg = ma
F/m - μg = a
So, substituting the values of the variables into the equation, we have
a = F/m - μg
a = 2850 N/300 kg - 0.45 × 9.8 m/s²
a = 9.5 m/s² - 4.41 m/s²
a = 5.09 m/s²
Since acceleration, a = (v - u)/t where u = initial velocity of log = 0 m/s (since it was a rest before being pulled out of the ditch), v = final velocity of log = 0.5 m/s and t = time taken for the log to reach a speed of 0.5 m/s.
So, making t subject of the formula, we have
t = (v - u)/a
substituting the values of the variables into the equation, we have
t = (v - u)/a
t = (0.5 m/s - 0 m/s)/5.09 m/s²
t = 0.5 m/s ÷ 5.09 m/s²
t = 0.098 s
t ≅ 0.1 s
