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zubka84 [21]
3 years ago
15

A car speeds up from rest to +16 m/ s in 4s. calculate the acceleration

Physics
2 answers:
Pani-rosa [81]3 years ago
6 0

The magnitude of acceleration is (change in speed) / (time for the change).

Change in speed = (speed at the end) - (speed at the beginning) =

                                   (16 m/s)  -  (0)  =  16 m/s .

Time for the change  =  4 s .

Magnitude of acceleration = (16 m/s) / (4 s) = 4 m/s per sec = 4 m/s² .


attashe74 [19]3 years ago
5 0
16 m/s - 0 m/s divided by 4s
= 16 m/s divided by 4s
= 4 m/s
The acceleration is 4 m/s squared
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What is it called when the right side of a design is reflected across a central axis and mirrored on the left side of the design
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Answer:

What is it called when the right side of a design is reflected across a central axis and mirrored on the left side of the design?

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3 years ago
Determine the amount of potential energy of a 5.0Kg book that is moved to three different shelves on a bookcase. The height of e
rjkz [21]
Formula to find gravitational potential energy:
mgh
m: mass
g: gravitational acceleration
h: height (relative to reference level)

so the P.E. at 1.0.m is (5x9.8x1)= 49J
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P.E. at 2.0m is (5x9.8x2)=98J
8 0
3 years ago
How are weather satellites and weather stations similar?
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6 0
4 years ago
Two ice skaters stand together as illustrated in the attached figure. They "push off" and travel directly away from each other,
Tema [17]
By definition, the momentum is given by:
 p = m * v
 Where,
 m = mass
 v = speed.
 On the other hand,
 F = m * a
 Where,
 m = mass
 a = acceleration:
 For the boy we have:
 p1 = m * v
 p1 = (F / a) * v
 p1 = ((710) / (9.81)) * (0.50)
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 For the girl we have:
 p2 = m * v
 p2 = (F / a) * v
 p2 = ((480) / (9.81)) * (v)
 p2 = 48.93 * v Kg * (m / s)
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6 0
3 years ago
Hooke’s law states that the distance that a spring is stretched by hanging object varies directly as the mass of the object. If
trasher [3.6K]

Answer:

d_{2} = 33.33 cm

Explanation:

Given:

When mass, m_{1} =21 kg

          distance travelled is  d_{1}  = 140 cm

When mass, m_{2} =5 kg

         distance travelled is  d_{2}  = ?

Hooke's law state that within elastic limit, when an external force is applied to a body, the body gets deformed and when the force is released the gets back to its original form.

Therefore according to the question,

\frac{d_{1}}{m_{1}}=\frac{d_{2}}{m_{2}}

\frac{140}{21}=\frac{d_{2}}{5}

d_{2} = 33.33 cm

Distance travelled is 33.33 cm when mass is 5 kg.

8 0
3 years ago
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