The value of the derivative of functions h'(6) as requested in the task content is; 55.
<h3>What is the value of h'(6)?</h3>
Since it follows from the task content that the function h(x)=4f(x)+5g(x)+1.
Hence, the derivative of h(x) can be evaluated as;
h'(x)=4f'(x)+5g'(x)
On this note, by substitution, it follows that;
h'(6)=4(5)+5(7)
h'(6) = 55.
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Answer:
The Answer is 9
Step-by-step explanation:
Answer:
Lines y = -x+4 and y= 3x+3 intersect the y-axis
Answer:
−16x+53
Step-by-step explanation:
Distribute
14−5(6−7)+18
↓
14−30+35+18
Add
14−30+35+18
↓
14−30+53
Combine like terms
14−30+53
↓
−16+53
Using it's concept, it is found that the domain for the expressions is, respectively, given by:
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<h3>What is the domain of a function?</h3>
It is the <u>set that contains all possible input values</u>.
In a fraction, the denominator cannot be zero, hence:
- The domain of the first two expressions is of
.
- The domain of the last expression is of
.
The third expression can be simplified, as:
(x + 5)/(x + 5) = 1.
The same is true for the fourth, as:
x²/x = 1.
Neither has any restriction, hence their domain is all real numbers, represented by
.
More can be learned about the domain of a function at brainly.com/question/25897115