Answer:
The sweat chloride reference value is less than 30 mmol/L. A value of more than 60 mmol/L of chloride in the sweat is consistent with a diagnosis of cystic fibrosis. The values of 30-60 mEq/L may represent heterozygous carriers, these carriers cannot be accurately identified with a sweat chloride test.
Let’s x for guitar and y for drum
u got 8x + 10y = 130 and x + y = 14
calculator x = 5, y= 9 so 5 guitars and 9 drums were rented
Answer:

Step-by-step explanation:

cross multiply
(3s)(xj) = (160s)(5j)
rearrange to isolate x amount of juice
x =
= 266.67 parts of juice for 160 parts of soda
Answer:
66 in
Explanation:
the circumference can be calculated as:

Where d is the diameter and π is 22/7.
So, replacing the values, we get:

Therefore, the circumference is 66 in.