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Addition of 6q + 1 and q + 11 is 7q + 12
<em><u>Solution:</u></em>
Given that, we have to add the given two expressions
<em><u>Given expressions are:</u></em>
6q + 1 and q + 11
We have to add both the expressions
Addition of 6q + 1 and q + 11 = 6q + 1 + q + 11
Add the coefficients of same variable. Here "q" is present in two terms
Therefore, add 6q and q
Similarly, add the constants 1 and 11
<em><u>Thus finally addition is done as:</u></em>
Thus addition of 6q + 1 and q + 11 is 7q + 12
Let x, y and z denote the weighs of car X, car Y and car Z, respectively.
We know that car X weighs 136 more than car Z, this can be express by the equation:
We also know that Y weighs 117 pounds more than car Z, this can be express as:
Finally, we know that the total weight of all the cars is 9439, then we have:
Hence, we have the system of the equations:
To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:
Now that we have the value of z we plug it in the first two equations to find x and y:
Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.