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Ilya [14]
3 years ago
11

Consider x+4=x+8. What values could be substituted for x to make this a true number sentence?

Mathematics
1 answer:
Schach [20]3 years ago
8 0

This looks unusual but let's try it.

x+4=x+8

Let's move the x vales to the left and numbers to the right.

x-x=8-4

0=-4

Hm. This doesn't work, does it?

This equation has no solution. If you believe you typed it wrong, correct it in the comment seciton.

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Carys is checking her tax bill for the last year.
AfilCa [17]

Answer:

$7,440.

Step-by-step explanation:

$0-$11,000 = no tax.

$11,000-$43,000 = 20%.

$43,000-$150,000 = 40%.

The earnings over $150,000 = 45%.  etc....

$45,600, = Revenue

Tax is 11000-43000  is = 0.20 * (32000)

= 11000-43000 = 6400

Tax  is 43000-45,600 is  = 0.40 *(2600)

=  45,600-43000 = 1040

=6400+1040 =7440

3 0
4 years ago
What in 40 023 032 in word form??
krok68 [10]
Forty million, twenty-three thousand and thirty-two
5 0
3 years ago
Can someone please help me with 4
Readme [11.4K]
A. The slope is 2.79. For every year, an individual grows 2.79 inches?

I don't know what the units are, so I can't answer this problem correctly.
8 0
4 years ago
A credit card bill for $559 was due on September 14. Purchases of $289 were made on September 19, and $15 was charged on Septemb
Sunny_sXe [5.5K]

Answer: $623

Step-by-step explanation:

calculation of Finance charge due on October 14

(+) $ 559 due on sep 14, $ 559 * (19.5*31) / (100 * 365) = $ 9.20

(+) purchase $ 289 on sep 19, $ 289 * (19.5*26 ) / (100 * 365) = $ 2.42

(+) finance charge on sep 28, $ 18 *(19.5*17 ) / (100 * 365) = $ 0.17

(-) Repayment on 25 sep , $ 250 * (19.5*20 ) / (100 * 365) = (2.745)

Total finance charges from 14 sep to 14 oct = $ 9.7= appr. 10

Amount due on 14 October = $559+$289+$15+$11.855- $250

= $ 623

3 0
4 years ago
PLEASE HELP
kolbaska11 [484]

Answer:

  • a) P(x) = 32000*1.04^x
  • b) $37435
  • c) During year 7

Step-by-step explanation:

<u>Given</u>

  • Initial pay = $32000
  • Increase rate = 4%

a. <u>Formula</u>

  • P(x) = 32000*1.04^x

b. Year 5 is after 4 years, so we are looking for the value of P(4)

  • P(4) = $32000*1.04^4 = $37435

c. <u>P(x) = 40000, x = ?</u>

  • 40000 = 32000*1.04^x
  • 1.04^x = 40000/32000
  • 1.04^x = 1.25
  • log 1.04^x = log 1.25
  • x = log 1.25 / log 1.04
  • x = 5.69, this is 6 years after

The required number of the years is 6 + 1 = 7

3 0
3 years ago
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