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4 years ago

Can a right triangle be both scales and isosceles explain

Mathematics

1 answer:

IgorC [24]4 years ago

3 0

Answer:

Yes

Step-by-step explanation:

A right triangle may be isosceles or scalene. In an obtuse triangle, one angle is greater than a right angle—it is more than 90 degrees. An obtuse triangle may be isosceles or scalene. In an acute triangle, all angles are less than right angles—each one is less than 90 degrees

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At a high school, the probability that a student takes a science class and a history class is 0.48. The probability that a stude

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Solutions

Probability: number of favourable outcomes
__________________________

total number of possible outcomes

In general, the total number of possible outcomes can be determined by multiplying the number of possible outcomes for each event.

P(A|B)= $\frac{P(A,B)}{P(B)}$

P(A|B) ⇒ P(taking history | taking science) , Therefore A corresponds to taking history, B corresponds to taking science.

P(A,B) will be the probability that a student is taking both of the subjects.

P(B) is the probability that a student is taking the subject science (regardless of whether he/she takes history or not)

Now to solve the problem you plug in the given numbers.

0.48 ÷ 0.82

0.48 is the Probability of (A,B) and 0.82 is the Probability of (B)

= 0.58537

Rounded to 0.59

Answer = (D)

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4 years ago

A company uses three different assembly lines- A1, A2, and A3- to manufacture a particular component. Of thosemanufactured by li

hammer [34]

Answer:

The probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

Step-by-step explanation:

The three different assembly lines are: A₁, A₂ and A₃.

Denote R as the event that a component needs rework.

It is given that:

$P (R|A_{1})=0.05\\P (R|A_{2})=0.08\\P (R|A_{3})=0.10\\P (A_{1})=0.50\\P (A_{2})=0.30\\P (A_{3})=0.20$

Compute the probability that a randomly selected component needs rework as follows:

$P(R)=P(R|A_{1})P(A_{1})+P(R|A_{2})P(A_{2})+P(R|A_{3})P(A_{3})\\=(0.05\times0.50)+(0.08\times0.30)+(0.10\times0.20)\\=0.069$

Compute the probability that a randomly selected component needs rework when it came from line A₁ as follows:

$P (A_{1}|R)=\frac{P(R|A_{1})P(A_{1})}{P(R)}=\frac{0.05\times0.50}{0.069} =0.3623$

Thus, the probability that a randomly selected component needs rework when it came from line A₁ is 0.3623.

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3 years ago

Using the formula r=d/t where d is the distance in miles, r is the rate and t is the time in hours at which rate must you travel

valentina_108 [34]

$r = \frac{337.5}{4.5} \\ r = 75$
the answer is c-75mph

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WILL MARK! Please help:) Find x so that this quadrilateral is a parallelogram.

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Answer:

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Answer:

c is the answer

Step-by-step explanation:

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