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SSSSS [86.1K]
2 years ago
14

What is the simplified form of 3 over 2x plus 5 + 21 over 8 x squared plus 26x plus 15 ?

Mathematics
1 answer:
Ivan2 years ago
6 0
The simplified form of 3 over 2x plus 5 + 21 over 8 x squared plus 26x plus 15 is <span>6 over the quantity 4 x plus 3.

</span>

The solution would be like this for this specific problem:

( 3 /( 2x+5 )) + ( 21 / (8x^2 + 26x + 15))
= ( 3 /( 2x+5 )) + ( 21 / (8x^2 + 20x + 6x + 15))
= ( 3 /( 2x+5 )) + ( 21 / (4x(2x + 5) + 3(2x + 5))
= ( 3 /( 2x+5 )) + ( 21 /(2x + 5)(4x + 3)
= [ 3 (4x + 3) + 21 ] /(2x + 5)(4x + 3)
= [ 12x + 9 + 21 ] /(2x + 5)(4x + 3)
= [ 12x + 30 ] /(2x + 5)(4x + 3)
= 6(2x + 5) /(2x + 5)(4x + 3)
= 6 / (4x + 3)

<span>I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.</span>

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What is the perimeter of the rectangle? Plato
charle [14.2K]

it depends how long the width and the length is. If the length is 5 cm and the width is 4 cm the perimeter will be 18cm. All you have to do is 5 doubled because there 2 sides for the length and 4 doubled because there are 2 sides for the width. I hope I have answered your question. XD

3 0
3 years ago
Read 2 more answers
I can’t figure out the solution I think it is y &lt; -10
Olenka [21]

Hey there!

  • <em>With negatives (-) you have to switch your symbol to the other way</em>
  • \bold{\frac{y}{-2}\leq5}
  • Firstly, substitute the \bold{y\ value  } as an invisible 1
  • So, now we have to flip the equation around
  • \bold{\frac{-1}{2}y\leq5}
  • We have to \bold{multiply} by \bold{-2} on each of your sides
  • \bold{-2\times\frac{-1}{2}\leq-2\times5}
  • \bold{Cancel \ out:2\times\frac{-1}{2}y \ because \ it \ equal \ 1}
  • \bold{Keep: -2\times5 \ because \ it \ helps \ us \ find \ our \ answer}
  • \bold{-2\times5=-10}
  • \boxed{\boxed{\bold{Answer:y\geq-10}}}\checkmark

Good luck on your assignment  and enjoy your day!

~\frak{LoveYourselfFirst:)}

<em />

4 0
3 years ago
A bird traveled 4 miles north before stopping to rest. The bird then flew 2,640 yards south in search of food. Finally, it flew
ra1l [238]
7 and 1/2 mile because 2,640=1.5 miles
4-1.5=2.5+5=7.5
8 0
2 years ago
The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
1 year ago
For a sequence an=an-1+an-2 and a1=1, a2=2, find its first four terms<br>​
ASHA 777 [7]

Answer:

3, 5, 8, 13

Step-by-step explanation:

aₙ = aₙ₋₁ + aₙ₋₂

a₃ = a₂ + a₁ = 2 + 1 = 3

a₄ = a₃ + a₂ = 3 + 2 = 5

a₅ = a₄ + a₃ = 5 + 3 = 8

a₆ = a₅ + a₄ = 8 + 5 = 13

7 0
3 years ago
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