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Lina20 [59]
3 years ago
12

A chef is going to use a mixture of two brands of Italian dressing. The first brand contains 8% vinegar, and the second brand co

ntains 13% vinegar. The chef wants to make 380 milliliters of a dressing that is 12% vinegar. How much of each brand should she use?
Mathematics
1 answer:
jok3333 [9.3K]3 years ago
8 0

Answer:

76 mL of 8% and 304 mL of 13%

Step-by-step explanation:

Set up a table like this (this is the same table for any mixture problem):

                   mL total     *           % vinegar       =              % vinegar/mL

8%

13%

total %

What you do with this table is multiply the first 2 columns and they equal the last column.  We already know the middle column's entries from what we are given.  But remember that a percent needs to be expressed as a decimal:

                       mL total     *       % vinegar      =        % vinegar/mL

8%                                                 .08

13%                                                .13

total %                                  

Now we also know that the total he wants to make is 380 mL that is 12%, so all that info goes into the last row:

                      mL total       *       % vinegar        =        % vinegar/mL

8%                                                   .08

13%                                                  .13

total %            380                          .12

If he wants this total mixture to come from the 8% and the 13% vinegars, he is mixing them together, or adding them.  We need to know how much 8% + how much 13% will give us 380 mL of 12%.  So we can fill in the amounts accordingly.  If he has x mL of 8%, then he will have 380 - x of 13%.  The table tells us that we are multiplying the first 2 columns to get the third, so we will do that at the same time:

                       mL total         *          % vinegar        =        % vinegar/mL

8%                        x                *             .08                =          .08x

13%                 380 - x            *             .13                 =      .13(380 - x)

total %               380              *             .12                 =          45.6

Since we are adding the different vinegars together to get the total, we can do that with the last column as well.  This is our equation:

.08x + .13(380 - x) = 45.6  Multiply everything through by 100 to get rid of the decimals now:

8x + 13(380 - x) = 4560 and

8x + 4940 - 13x = 4560 and

-5x = -380 so

x = 76

This means that there is 76 mL of 8% and 380 - 76 = 304 mL of 13%

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