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kari74 [83]
3 years ago
8

How to solve it?........................

Mathematics
1 answer:
Feliz [49]3 years ago
5 0
5x+4=114
5x= 110
X=22

114+ 3(22)-24=156
180-156=24
2y=24
Y=12
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Easy points..........
IRINA_888 [86]

Answer:

  • 38°; 142°; 308°

Step-by-step explanation:

The solution of each question is self-explanatory.

<u>Used properties</u>

  • Vertical angles are congruent
  • Angle sum property of circle
  • Central angle is same as intercepted arc measure
<h3>#8</h3>
  • mED = mAB = mAC - mBC = 90° - 52° = 38°
<h3>#9</h3>
  • mEA = mBCD = mBC + mCD = 52° + 90° = 142°
<h3>#10</h3>
  • mBDC = 360° - mBC = 360° - 52° = 308°
5 0
2 years ago
Select no solution, one solution, or infinitely many solutions for each question
topjm [15]

Answer:

Step-by-step explanation:

1. no sol

2. infi

3.no sol

4. one sol

5 0
3 years ago
30 points!!!
olya-2409 [2.1K]

Answer:

The cost he will pay for 10 rides will be $70 and for r rides will be .

Step-by-step explanation:

The price of admission into the park is $20.The price for each ride is $5David takes 10 rides,So, the cost he will pay if he took 10 rides will be,If he had r rides,So, the cost he will pay if he took r rides will be,Therefore, the cost he will pay for 10 rides will be $70 and for r rides will be.

!!! hope this helps !!!!

6 0
2 years ago
Read 2 more answers
Help me with this!! Will mark Brainliest
ollegr [7]

Answer:

yes both are the distance of 99mm

3 0
3 years ago
Read 2 more answers
Use Theorem 7.4.1. THEOREM 7.4.1 Derivatives of Transforms If F(s) = ℒ{f(t)} and n = 1, 2, 3, . . . , then ℒ{tnf(t)} = (−1)n dn
Ugo [173]

Answer:

L\left(te^{2t }sin3t\right)=\frac{6s-12}{(s^2-4s+13)^2}.

Step-by-step explanation:

If F(s)= L{f(t)}

Then L\left\{(t^nf(t)\right\}=(-1)^n\frac{\mathrm{d^n}F(s)}{\mathrm{d^n}s}

L\left\{te^{2t}sin3t\right\}

f(t)=e^{2t}sin3t

L\left\{e^{at}sinbt\right\}=\frac{b}{(s-a)^2+b^2}

Therefore,L\left\{e^{2t}sin3t\right\}=\frac{3}{(s-2)^2+(3)^2}

L\left\{e^{2t}sin3t\right\}=\frac{3}{s^2-4s+13}

L\left\{te^{2t}sin3t\right}=-\frac{\mathrm{d}F(s)}{\mathrm{d}s}

=-\frac{\mathrm{d}e^{2t}sin3t}{\mathrm{d}s}

L\left\{te^{2t}sin3t\right\}

=\frac{3(2s-4)}{(s^2-4s+13)^2}

L\left\{te^{2t}sin3t\right\}=\frac{6s-12}{(s^2-4s+13)^2}.

7 0
4 years ago
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