A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
Answer:
Step-by-step explanation:
So first let us break how much trinkets one worker can make and find out the time frame. So the first two workers each can make a trinket in 90 seconds, 90/2 is 45 (seconds) for 1 worker. And the third worker takes 10 seconds longer, so 45+10 is 55 seconds for the third worker to make 1 trinket. There are 60 minutes in a hour, 60x60(seconds) is 3600 seconds in an hour. But here we will have to do 3600/100, because we forget about the individual time and focus on the combined time. So we add 10 more to 90, and now get 3600/100, which gives us out result of 36 trinkets made in an hour
sorry it took long i burnt my brain for this one
Answer:no
There both the same because just the differnce is the last number which is zero.
Step-by-step explanation:
All you got to do is find the answer and thats all
Plzz mark brainlest and thank me
Answer:
it might be 390
Step-by-step explanation:
hope this helps
1/4 of the squares aren’t shaded