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marshall27 [118]
3 years ago
12

Robert earns $512.75 less than Noel. John earns 3 times Robert's salary. If the total salary earned by them is $47,645.25, how m

uch salary does Robert earn?
Mathematics
2 answers:
babymother [125]3 years ago
6 0

Answer: Robert earned $9426.5

Step-by-step explanation:

Let x represent the amount earned by Robert.

Let y represent the amount earned by Noel.

Let z represent the amount earned by John.

Robert earns $512.75 less than Noel. This is expressed as

y = x + 512.75

John earns 3 times Robert's salary. This is expressed as

z = 3x

If the total salary earned by them is $47,645.25, it means that

x + y + z = 47645.25 - - - - - - - - - - -1

Substituting z =3x and y = x + 512.75 into equation 1, it becomes

x + x + 512.75 + 3x = 47645.25

x + x + 3x = 47645.25 - 512.75

5x = 47132.5

x = 47132.5/5

x = 9426.5

y = x + 512.75 = 9426.5 + 512.75

y = 9939.25

z = 3x = 3 × 9426.5

z = 28279.8

FrozenT [24]3 years ago
3 0

Answer: Robert earns$9426.50

Step-by-step explanation:

Complete question: Robert earns $512.75 less than Noel

noel's salary = x, robert's salary = y and john's salary = z

y = x - 512.75 ..........(1)

z = 3y = 3(x - 512.75) = 3x - 1538.25 ...............(2)

x + y + z = 47645.25..........................(3)

substitute for y and z

x + (x - 512.75) + (3x - 1538.25) = 47645.25

x + x - 512.75 + 3x - 1538.25 = 47645.25

5x = 47645.75 + 512.75 + 1538.25

5x = 49696.25

divide both sides by 5

x = 9939.25 ..... noel's salary

to get robert's salary substitute x in equation 1

y = 9939.25 - 512.75 = 9426.50

y = $9426.50..... robert's salary

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Hey there!!

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We will find the length of the square.

Square area = side²

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side = 5 yards.

Now convert this into inches

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6 0
3 years ago
There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o
Anastaziya [24]

P(B/A) is \frac{5}{9} in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

  • P(B|A) is called the "Conditional Probability" of B given A
  • Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
  • The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

   marbles in the jar

∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

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- That means red is already occurred when green is happened,

  so it is a "Conditional Probability" of green given red

  P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

   the first draw

∴ P(A) = P(red)

∵ P(red) = \frac{3}{10}

∴ P(A) = \frac{3}{10}

∵ Event B is defined as drawing a green marble on the second draw

∴ P(B) = P(green)

- The number of marbles after the red is chosen is 9

∵ P(green) = \frac{5}{9}

∴ P(B) = \frac{5}{9}

- Find P( A and B)

∴ P(A and B) = ( \frac{3}{10} ) . ( \frac{5}{9} )

∴ P(A and B) = \frac{15}{90}

- Simplify the fraction by divide up and down by 15

∴ P(A and B) = \frac{1}{6}

∵ P(B|A) = P(A and B)/P(A)

- Substitute the values of P(A and B) and P(A) in the rule above

∴ P(B/A) = \frac{\frac{1}{6}}{\frac{3}{10}}

- Simplify the fraction

∵ \frac{1}{6} ÷ \frac{3}{10} = \frac{1}{6} × \frac{10}{3} = \frac{10}{18}

- Divide up and down by 2

∴ P(B/A) = \frac{5}{9}

P(B/A) is \frac{5}{9} in the simplest form

Learn more:

You can learn more about probability in brainly.com/question/10744457

#LearnwithBrainly

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How to solve -27/x^15
kompoz [17]

Answer:

\frac{-27}{x^{15}}=-\frac{27}{x^{15}}

Step-by-step explanation:

<em>If you just want to simplify -27/x^15, it is not very difficult. Here is the simple way.</em>

<em />

Given the expression

\frac{-27}{x^{15}}

solving

\frac{-27}{x^{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

=-\frac{27}{x^{15}}

Therefore,

\frac{-27}{x^{15}}=-\frac{27}{x^{15}}

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