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dsp73
3 years ago
13

Walter is making a 300-mile trip from Wichita Falls, Texas to Austin, Texas. After the first 120 miles, he continues driving at

65 mph.
If the equation 120+65x=300 is used to describe this situation, what does the " x " represent?
Mathematics
2 answers:
Contact [7]3 years ago
8 0

Answer:

distance left

Step-by-step explanation:

kkurt [141]3 years ago
4 0

Answer:

about 135 more miles to go

Step-by-step explanation:

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For ssc
Inga [223]

Answer:

Average speed is 3 kilometers an hour

4 0
2 years ago
The expression below is the factorization of what trinomial-1(x+5)(x+6)
Nadya [2.5K]

Answer:

-x^2 - 11x -30

Step-by-step explanation:

Solve using foiling. Ignore the -1 to begin with and just look at the part in parenthesis. Do x from the first parenthesis times the stuff in the second parenthesis.

ie: x(x) and x(6)

ie: x^2 + 6x

Then do the 5 times the things in the second parenthesis.

ie: 5(x) and 5(6)

ie: 5x + 30

Then add what you got from multiplying the first value to what you got from multiplying the second.

ie: x^2 + 11x + 30

This is a trinomial because it has three different variables. Now change all the signs to negative because of the -1 out front.

ie: -x^2 - 11x -30

4 0
2 years ago
Y= 3x+7<br> y = -2x-3<br> What would be the x and y for that solution
alexandr402 [8]

Answer:

So if we are solving for x and y. First we need to subtract both equations. We take each equation and put in parenthesis and subtract.

y-y = (3x+7)-(-2x-3) =

0 = 3x+7+2x+3

0 = 5x+10

-10 = 5x

-2 = x.

Now we need to solve for y.

Plug it in for the first equation. -2*3+7 = -6+7 = 1

Test if we are correct and try in the second equation.

-2*-2-3 = 4-3 = 1

<u>x = -2</u>

<u>y = 1</u>

6 0
3 years ago
I know the answer just need someone explain to me how to solve it
Vinvika [58]

The logarithm of a quotient can be written as a difference of logarithms:

\log_3\left(\dfrac uv\right) = \log_3(u) - \log_3(v)

You can also think of this as a combination of the product-to-sum and reciprocal/power properties of logarithms:

\log_3\left(\dfrac uv\right) = \log_3\left(u \times \dfrac1v\right) = \log_3(u) + \log_3\left(\dfrac1v\right) = \log_3(u) - \log_3(v)

To summarize,

\log_b(mn) = \log_b(m)+\log_b(n)

\log_b\left(\dfrac mn\right) = \log_b(m) - \log_b(n)

\log_b\left(m^n\right) = n \log_b(m)

3 0
2 years ago
Are there concepts/processes to strictly follow in writing radicals as expressions with rational exponents?
Eva8 [605]

Answer:

The concept or process is x^{\frac{m}{n}}=(\sqrt[n]{x})^m.

Step-by-step explanation:

Consider the provided information.

The following property can be used to rewrite each radical as an exponent.

The numerator tells the power of the resulting rational exponent, and the denominator of the rational exponents tells the root of that number.

x^{\frac{m}{n}}=(\sqrt[n]{x})^m

For example:

(27)^{\frac{2}{3}}=(\sqrt[3]{27})^2

(27)^{\frac{2}{3}}=(3)^2

(27)^{\frac{2}{3}}=9

Hence, the concept or process is x^{\frac{m}{n}}=(\sqrt[n]{x})^m.

5 0
3 years ago
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