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damaskus [11]
3 years ago
15

7. An auto's velocity increases uniformly from 3m/s to 25m/s while

Physics
1 answer:
AnnyKZ [126]3 years ago
7 0

Answer:

  3.422 m/s^2

Explanation:

A useful relation is ...

  v2^2 -v1^2 = 2ad

  (25 m/s)^2 -(3 m/s)^2 = 2a(90 m)

  (616 m^2/s^2)/(180 m) = a ≈ 3.422 m/s^2

The acceleration is about 3.422 m/s^2.

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Let us be two cylindrical conductors connected in parallel, to which a potential difference of V = 170V is applied. The two cond
PSYCHO15rus [73]

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

<h3>Resistance</h3>

Resistance is a measure of the opposition to flow of electric current. It is measured in ohms.

It is given by the formula:

R=\rho\frac{l}{A} \\\\where\ l=length,A=area,\rho=resistivity

Given that R₂ = 469 ohm, hence:

R_2=\rho\frac{l_2}{A_2} \\\\469=\rho\frac{l_2}{\pi r_2^2}

But l₁ = 6l₂, r₁ = (1/5)r₂, hence:

R_1=\rho \frac{l_1}{A_1}=\rho *\frac{6l_2}{[\pi (1/5)r_2]^2} =150 * \rho \frac{l_2}{[\pi r_2]^2}=30*469=70350\ ohm

The equivalent resistance (R) is:

R=\frac{R_1R_2}{R_1+R_1}=\frac{469*70350}{469+70350}  =466\ ohm

The equivalent resistance of the two cylindrical conductors connected in parallel is 466 ohm.

Find out more on resistance at: brainly.com/question/17563681

3 0
2 years ago
Dimensional formula of Amplitude ?​
jeka57 [31]

Answer:

The dimensional formula of the amplitude of a wave is given by,

[ M⁰L¹T⁰ ]

Where,

M = Mass

L = Length

T = Time

Derivation

The amplitude of wave = Maximum displacement

Since, the dimensional formula of displacement = [ M⁰L¹T⁰ ]

Therefore, the amplitude of a wave is dimensionally represented as [ M⁰L¹T⁰ ]

5 0
2 years ago
What is the wavelength of a wave traveling with a wave speed of 1348 m/s
saw5 [17]

Answer:    f = 4 Hz i think

Explanation:

sorry i dont rember (cant type lol)

5 0
2 years ago
In 8,450 seconds, the number of radioactive nuclei decreases to 1/16 of the number present initially. What is the half-life (in
almond37 [142]

Answer:

<h2>2113 seconds</h2>

Explanation:

The general decay equation is given as N = N_0e^{-\lambda t} \\\\, then;

\dfrac{N}{N_0} = e^{-\lambda t} \\ where;

N/N_0 is the fraction of the radioactive substance present = 1/16

\lambda is the decay constant

t is the time taken for decay to occur = 8,450s

Before we can find the half life of the material, we need to get the decay constant first.

Substituting the given values into the formula above, we will have;

\frac{1}{16} = e^{-\lambda(8450)}  \\\\Taking\ ln\ of \both \  sides\\\\ln(\frac{1}{16} ) =  ln(e^{-\lambda(8450)})  \\\\\\ln (\frac{1}{16} )  = -8450 \lambda\\\\\lambda = \frac{-2.7726}{-8450}\\ \\\lambda = 0.000328

Half life f the material is expressed as t_{1/2} = \frac{0.693}{\lambda}

t_{1/2} = \frac{0.693}{0.000328}

t_{1/2} = 2,112.8 secs

Hence, the half life of the material is approximately 2113 seconds

7 0
3 years ago
40 Points!!!!!!!
marshall27 [118]
D. Ted associated being asked a question with embarrassment.
7 0
3 years ago
Read 2 more answers
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