Answer:
F = 33.12 N
Explanation:
given,
first force = 15 N is oriented at 58.0° counterclockwise
second force = (−19.0 N,18.5 N)
x-component of first force = 15 cos 58.0° = 7.95 N
y-component of second force = 15 sin 58.0° = 12.72 N
second component
now,
F netx = 7.95 - 19 = -11.05 N
F nety = 12.72 + 18.5 = 31.22 N
F = 33.12 N
θ = -70.51°
Answer:
v2 = 12m/s
Explanation:
To find the velocity of water in the lower tube you use the following formula:
(1)
v1: velocity in the first tube
v2: velocity in the second tube
A1: area of the first tube
A2: area of the second tube
From the expression (1) you can obtain the velocity v2, that is the velocity of water in the second tube:
you replace the values of the parameter in order to calculate v2:
hence, the velocity of the water is 12m/s
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