Imagine an object is moving in one dimension on a number line, and for this we'll say that the numbers on the line are a metre apart. If the object moves from 2 m to 7 m, the change in position is 7-2=+5 metres. But if the object moves back from 7 m to 2 m, the change in position is 2-7=-5 metres. since 
, and time is always positive, velocity will be positive in one direction and negative in the other direction.
If a 12 kg cat is sitting 5 m up in a tree, how much PE does it have?
1 answer:
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Answer:
By a factor of 1/4.
Explanation:
The impulse force that applies to an object undergoing rapid deceleration just before coming to a stop on the ground is given by the following formula,
in which ,
represent the change in momentum and the time taken for that change.
If one increases the time that is taken for the momentum change (which remains constant for this situation) by a factor 4 and if that new force is represented by , the following manipulation confirms the answer to this question.
Here is the force that was applied to the object previously.
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