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anastassius [24]
3 years ago
10

I need help

Physics
1 answer:
Fudgin [204]3 years ago
8 0
This question involves the conservation of momentum. The system under consideration will be the two cars.
Total momentum before collision = total momentum after collision
momentum = mass x velocity
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
480 x 14.4 + 570 x 13.3 = 480v₁ + 570 x 14
v₁ = 13.6 m/s
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How large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius
maria [59]

Answer:

897

Explanation:

Speed of the car, v = 126 km/h, converting to m/s, we have v = 35 m/s and

Radius of the curve, R = 150 mm = 0.15 m

The centripetal acceleration a(c) is given by the formula = v² / R so that

a(c) = 35² / 0.15

a(c) = 1225 / 0.15

a(c) = 8167 m/s²

The force that causes the acceleration is frictional force = µ m g, where

µ = coefficient of friction

m = the mass of the car and

g = acceleration due to gravity, 9.81

From Newton's law:

µ m g = m a(c) , so that

µ = a(c) / g

µ = 8167 / 9.81

µ = 897

Therefore, the coefficient of static friction must be as big as 897

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3 years ago
Orsted found that the needle of a compass could be redirected if placed near a wire carrying current. This illustrated a fundame
cricket20 [7]

Answer:

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4 0
3 years ago
a 2.6 kg block is attached to a horizontal spring that has a spring constant of 126 N/m. At the instant when the displacement of
NeTakaya

Answer:

The acceleration of the object is 5.57\ m/s^2.

Explanation:

Given that,

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When the block is displaced, the force acting on the spring is equal to the force due to its motion. Such as :

kx=ma

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