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3 years ago

What times what equals 400

1 answer:

7 0

If you're willing to consider fractions or decimals,
then there are an infinite number of answers.
Like (2.5 x 160), and (15 x 26-2/3).

If you want to stick to only whole numbers,
then these 8 combinations do:

1, 400
2, 200
4, 100
5, 80
8, 50
10, 40
16, 25
20, 20

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If a non-human civilization were to develop on Saturn's largest moon, Titan, its scientists might well develop a temperature sca

klasskru [66]

Answer: $-330.47 \°M$

Explanation:

Let's begin by explaining that the relation between the Celsius scale and Kelvin scale is:

$\°C +273.15=K$

This means the absolute zero point of the Kelvin scale is $0 K=-273.15 \°C$

Keeping this in mind, we have the freezing point and boling point of Methane as:

Freezing point: $0 \°M=-182.6 \°C=90.55 K$

Boiling point: $100 \°M=-155.2 \°C=117.95 K$

According to this, there is a linear relation between the methane scale ( $\°M$ ) and the Kelvin scale in the form:

$T=a+bt_{M}$ (1)

Where:

$T$ is the temperature in Kelvin

$t_{M}$ is the temperature in degrees Methane

Firstly, we need to find the value of $a$ and $b$ with the two given points ( $90.55 K$ and $117.95 K$ ):

When $T=90.55$ and $t_{M}=0$ :

$90.55=a+b(0)$

$a=90.55$ (2)

When $T=117.95$ and $t_{M}=100$ :

$117.95=90.55+b(100)$

$b=0.274$ (3)

Now we have the linear equation:

$T=90.55+0.274t_{M}$ (4)

Isolating $t_{M}$ :

$t_{M}=\frac{T-90.55}{0.274}$ (5)

Evaluating for $T=0 K$ :

$t_{M}=\frac{0-90.55}{0.274}$ (6)

Finally:

$t_{M}=-330.47 \°M$

This means $0 K=-330.47 \°M$

7 0

2 years ago

A plumbing branch is composed of 68' of 1" diameter Type L copper pipe, three 90-degree elbows (wrought), and a gate valve. The

valina [46]

Answer:

7.404 psi

Explanation:

See attachment please

5 0

3 years ago

A certain instant camera determines the distance to the subject by sending out a sound wave and measuring the time needed for th

valentinak56 [21]

The total distance covered by the sound wave is twice the distance between the camera and the subject (because the wave has to reach the subject and then travel back to the camera), so 2L, where L=3.42 m. The speed of sound is v=343 m/s. It is a uniform linear motion, so we can use the basic relationship between space (S), time (t) and velocity (v) to find the time the wave needs to return to the camera:
$t= \frac{S}{v}= \frac{2L}{v}= \frac{2\cdot 3.42 m}{343 m/s}=0.020 s$

6 0

3 years ago

A motorcycle daredevil plans to ride up a 2.0-m-high, 20° ramp, sail across a 10-m-wide pool filled with hungry crocodiles, and

il63 [147K]

Answer:

He becomes a croco-dile food

Explanation:

From the question we are told that

The height is h = 2.0 m

The angle is $\theta = 20^o$

The distance is $w = 10m$

The speed is $u = 11 m/s$

The coefficient of static friction is $\mu = 0.02$

At equilibrium the forces acting on the motorcycle are mathematically represented as

$ma = mgsin \theta + F_f$

where $F_f$ is the frictional force mathematically represented as

$F_f =\mu F_x =\mu mgcos \theta$

where $F_x$ is the horizontal component of the force

substituting into the equation

$ma = mgsin \theta + \mu mg cos \theta$

$ma =mg (sin \theta + \mu cos \theta )$

making a the subject of the formula

$a = g(sin \theta = \mu cos \theta )$

substituting values

$a = 9.8 (sin(20) + (0.02 ) cos (20 ))$

$= 3.54 m/s^2$

Applying " SOHCAHTOA" rule we mathematically evaluate that length of the ramp as

$sin \theta = \frac{h}{l}$

making $l$ the subject

$l = \frac{h}{sin \theta }$

substituting values

$l = \frac{2}{sin (20)}$

$l = 5.85m$

Apply Newton equation of motion we can mathematically evaluate the final velocity at the end of the ramp as

$v^2 =u^2 + 2 (-a)l$

The negative a means it is moving against gravity

substituting values

$v^2 = (11)^2 - 2(3.54) (5.85)$

$v= \sqrt{79.582}$

$= 8.92m/s$

The initial velocity at the beginning of the pool (end of ramp) is composed of two component which is

Initial velocity along the x-axis which is mathematically evaluated as

$v_x = vcos 20^o$

substituting values

$v_x = 8.92 * cos (20)$

$= 8.38 m/s$

Initial velocity along the y-axis which is mathematically evaluated as

$v_y = vsin\theta$

substituting values

$v_y = 8.90 sin (20)$

$= 3.05 m/s$

Now the motion through the pool in the vertical direction can mathematically modeled as

$y = y_o + u_yt + \frac{1}{2} a_y t^2$

where $y_o$ is the initial height,

$u_y$ is the initial velocity in the y-axis

$a_y$ is the initial acceleration in the y axis with a constant value of ( $g = 9.8 m/s^2$ )

at the y= 0 which is when the height above ground is zero

Substituting values

$0 = 2 + (3.05)t - 0.5 (9.8)t^2$

The negative sign is because the acceleration is moving against the motion

$-(4.9)t^2 + (2.79)t + 2m = 0$

Solving using quadratic formula

$\frac{-b \pm \sqrt{b^2 -4ac} }{2a}$

substituting values

$\frac{-3.05 \pm \sqrt{(3.05)^2 - 4(-4.9) * 2} }{2 *( -4.9)}$

$t = \frac{-3.05 + 6.9}{-9.8} \ or t = \frac{-3.05 - 6.9}{-9.8}$

$t = -0.39s \ or \ t = 1.02s$

since in this case time cannot be negative

$t = 1.02s$

At this time the position the motorcycle along the x-axis is mathematically evaluated as

$x = u_x t$

x $=8.38 *1.02$

$x =8.54m$

So from this value we can see that the motorcycle would not cross the pool as the position is less that the length of the pool

7 0

3 years ago

Which state of matter would be described as having low energy, with particles that are fixed in place and their only motion is v

Butoxors [25]

1. D) Solid

2. C) They are moving at high speeds and are far from each other

3. A) Gas

4.C) diagram C (as gas has the most kinetic energy so it moves and separates the most)

A)Gas (same question as 3)

5.C) melting

6.C) solid

7.D) condensation, energy is removed

8.D) B is Liquid , it’s freezing as energy is removed

9.A) Gas would change to vapour

10.B) Vaporisation

11. A) As temp increases energy of particles increase and substance changes from solid to liquid to gas

12. particles in a solid are more compact than in liquids and gases & solids maintain a fixed volume whereas liquids and gases are able to move more freely and their volume can change

6 0

2 years ago