Time t=2.4 minutes=2.4×60=144 seconds
distance s=1.2 miles=1.2×1609=1930.8 meters
speed v=s/t=1930.8÷144=[tex] \frac{1930.8}{144} = \frac{160.9}{12} =[/13.408m/s ~nearly]
Answer:
I'm not sure
Explanation:
I have had that question to Uchida c r go crew in to go be
Explanation:
Given that,
Initial velocity, u = 11.3 m/s
Angle above the horizontal,
Time of flight :
Horizontal distance traveled is given by :
x = ut
x = 11.3 m/s × 1.32 s
x = 14.916 m
Maximum height is given by :
Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.
Im not sure but it might be the last option: it gives reasons to be believed and trusted