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Lisa [10]
3 years ago
6

Each point on the edge of a circle is equidistant from the center of the circle. The center of a circle is located at (6, 3). Wh

ich point on the y-axis could be on the edge of the circle if the distance from the center of the circle to the edge is 10 units?
A.(0, –1)

B.(0, 1)

C.(0, 5)

D.(0, –5)
Please explain. 
Mathematics
2 answers:
vladimir2022 [97]3 years ago
5 0

Answer:

yes its A

Step-by-step explanation:

kirill115 [55]3 years ago
3 0

Answer:

(0, –5)

Step-by-step explanation:

If you don't see this option there is another option, (0 , 11) is also correct

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What is the solution to the system of equations? Use the substitution method.
BabaBlast [244]
The answer is:
4x+2y=11}  4x+2y=11} x=2-2y
x-2=-2y    }  x+2y=2    } x=2-2(-3/6)
                                      x=2-(-6/6)
4(2-2y)+2y=11              x=2-(-1)
8-8y+2y=11                   x=3
8-6y=11
-6y=11-8
-6y=3/-6
y=-3/6=-1/2

So for my opinion the solution is A.(3,-1/2)
4 0
2 years ago
Add 8x+6yz-3zx, 4yz+6zx-8y, -3xz+6x-4xy<br><br> pls find answer...
Butoxors [25]
Na bro i dont even know what’s that tbh
3 0
2 years ago
Dany has a business selling bracelets for 7.50 each. She only has enough material to make 5 bracelets. If x represents the numbe
ziro4ka [17]

Answer:

The range is [0,37.5]

Step-by-step explanation:

We start by writing the equation that links x and y

From the question;

y = 7.5x

Now, she has enough material to make 5 only

When we talk of range, we are referring to the values on the y-axis

So the lowest y value is 0

and since the highest number of bracelets is 5;

The total cost of the 5 is 7.5(5) = 37.5

So the range is [0,37.5]

6 0
2 years ago
I need help plsss help
Fed [463]

Answer:

Triangle: True

Parallelogram: False, area is 63cm^2

Trapezoid: True

Step-by-step explanation:

Use area calculators on the internet to find the area of shapes.

3 0
2 years ago
Change the following number to Scientific Notation.<br> 0.0080098
AlladinOne [14]
Simple

scientific notation
8.009 × 10-3
4 0
3 years ago
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