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MA_775_DIABLO [31]
1 year ago
5

Write an absolute value equation or inequality to describe each graph

Mathematics
1 answer:
Rina8888 [55]1 year ago
6 0

Step-by-step explanation:

|x|   \geqslant 1.5

Or basically,

x  \geqslant 1.5

or

x \leqslant  - 1.5

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Margot gave 10% of x number of dollars that she earned over the summer to an animal rescue shelter. 10% of x is about $60.00. Ch
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4 3⁄4 feet = how many inches
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Can it be solve pq(r²+1)-r(p²+q²)
ivann1987 [24]

Answer:

pqr²+pr-rp²+rq²

Step-by-step explanation:

pq(r²+1)-r(p²+q²)

pqr²+pr-rp²+rq²

3 0
1 year ago
A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0
3 years ago
A video store charges $8 to rent a video game. You must be a member to rent from the store, but
mote1985 [20]

Answer:

10 is the amount of video game you need to rent to equal each other

Step-by-step explanation:

Video store A is 8x

Video store B is 3x+50

8x = 3x +50

5x = 50

x= 10

6 0
2 years ago
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