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miss Akunina [59]

2 years ago

13

Martina took out a loan for 7 months and was charged simple interest at an annual rate of 7.2%. The total interest she pald on t

he loan was $231. How much money did Martina borrow? Do not round any intermediate computations.

1 answer:

ycow [4]2 years ago

8 0

Answer:

70 thats it bro

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If 3/x=5/y then what is the value of y/x?<br> plss help

netineya [11]

Answer:

Step-by-step explanation:

3/x=5/y

3y/x=5

y/x=5/3

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3 years ago

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erastovalidia [21]

92/25=3.68 I hope this help

3 0

3 years ago

Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?

gladu [14]

Sum:

3x^5*y - 2x^3*y^4 - 7x*y^3
+ -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
-5x^5y - 6xy^3

Term 1: Degree = 6
Term 2: Degree = 4

Difference:

3x^5*y - 2x^3*y^4 - 7x*y^3
- -8x^5*y + 2x^3*y^4 +x*y^3
---------------------------------------
11x^5y - 4<span>x^3*y^4 - 8</span>xy^3

Term 1: Degree = 6
Term 2: Degree = 7
Term 3: Degree = 4

The degree of a term of a polynomial can be obtained by adding the exponents of the variables in that term.

5 0

3 years ago

Whats the square root of 15?

lapo4ka [179]

Answer:

The square root of 15 in exact form but in decimal form its 3.87298334

Step-by-step explanation:

8 0

2 years ago

One household is to be selected at random from a town. The probability that the household has a cat is 0.20.2 . The proba

dimulka [17.4K]

Answer:

There is a 50% probability that the household has a dog, given that the household has a cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a household has a cat but not a dog and $A \cap B$ is the probability that a household has both a cat and a dog.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that the household has a cat or a dog is 0.5

$a + b + (A \cap B) = 0.5$

The probability that the household has a dog is 0.4

$B = 0.4$

$B = b + (A \cap B)$

$b = 0.4 - (A \cap B)$

The probability that the household has a cat is 0.2.

$A = 0.2$

$A = a + (A \cap B)$

$a = 0.2 - (A \cap B)$

So

$a + b + (A \cap B) = 0.5$

$0.2 - (A \cap B) + 0.4 - (A \cap B) + (A \cap B) = 0.5$

$A \cap B = 0.1$

What is the probability that the household has a dog, given that the household has a cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

$P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5$

There is a 50% probability that the household has a dog, given that the household has a cat.

4 0

3 years ago