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zlopas [31]
4 years ago
14

Can someone please help

Mathematics
1 answer:
posledela4 years ago
3 0

Well first you multiply 525x700 I got 367,500 but then you have to deduct the amount on stage so make that 360,000

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3h − j when h = 8 and j = 11
Tamiku [17]

Answer:

13

Step-by-step explanation:

h = 8

j = 11

3h - j

= 3(8) - 11

= 24 - 11

= 13

7 0
3 years ago
Espana
marysya [2.9K]
First, subtract to get the difference.
2.85 – 2.78 = 0.07

Next, divide 2.78 by 100
2.78 ÷ 100 = 0.0278
So, 0.0278 is 1%. Divide 0.07 by 0.0278 to get the answer.
0.07 ÷ 0.0278 ≈ 2.518
2.518 ≈2.5
Therefore, the percentage increase is approximately 2.5% (that's the answer).

Hope this helps!
8 0
3 years ago
A box of cereal states that there are 96 calories in a 3/4
IgorC [24]

Answer:

112 calories per cup

Step-by-step explanation:

Let x = unit rate for calories per cup,

Then (3/4)*x = 84

and x = 84*(4/3) = 112 calories per cup

3 0
3 years ago
Read 2 more answers
50 POINTS !!
Anna35 [415]

Answer:

Step-by-step explanation:

Hope this helps u!!

7 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

5 0
2 years ago
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