Answer:
1. Nominal
2. Interval
3. Interval
4. Nominal.
Step-by-step explanation:
Nominal scales are used when the variable we're interested in has NO quantitative value.
Therefore, the college you are enrolled in and your hometown are examples of nominal data.
Interval scales are used when the variable we are interested in has quantitative value and the values have an order and the difference between each value is the same.
For the case of number of students, we know, for example, that 20 students < 21 students, and the difference between 20 and 21 is the same as the one between 21 and 22. The same applies for the age of your classmates.
Therefore, the age of your classmates and the number of students in a statistics course is an interval data.
Answer:
see below
Step-by-step explanation: 7 1 16 33
y = x² translated t the point (3, 2) y = 0 when x = 0
y = (x - 3)² moves the function three units to the right y = 0 when x = -3
y = (x-3)² + 2 moves the function up 2 units y = 2 when x = -3
y = (x-3)² + 2
y = x² - 6x + 9 + 2
y = x² - 6x +11
graph the equations x², (x-3)² + 2, and x² - 6x + 11 to verify (I did)
Searching for the answer right now.
The proper equation for midpoints is inside the following photo
Answer:
- KEi = 2.256×10^5 J
- KEf = 9.023×10^5 J
- 4 times as much work
Step-by-step explanation:
The kinetic energy for a given mass and velocity is ...
KE = (1/2)mv^2 . . . . . m is mass
At its initial speed, the kinetic energy of the car is ...
KEi = (1/2)(810 kg)(23.6 m/s)^2 ≈ 2.256×10^5 J . . . . . m is meters
At its final speed, the kinetic energy of the car is ...
KEf = (1/2)(810 kg)(47.2 m/s)^2 ≈ 9.023×10^5 J
The ratio of final to initial kinetic energy is ...
(9.023×10^5)/(2.256×10^5) = 4
4 times as much work must be done to stop the car.
_____
You know this without computing the kinetic energy. KE is proportional to the square of speed, so when the speed doubles, the KE is multiplied by 2^2 = 4.
