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3 years ago

Determine whether the following possible responses should be classified as ratio, interval, nominal or ordinal data.

Mathematics

1 answer:

nexus9112 [7]3 years ago

3 0

Answer:

1. Nominal

2. Interval

3. Interval

4. Nominal.

Step-by-step explanation:

Nominal scales are used when the variable we're interested in has NO quantitative value.

Therefore, the college you are enrolled in and your hometown are examples of nominal data.

Interval scales are used when the variable we are interested in has quantitative value and the values have an order and the difference between each value is the same.

For the case of number of students, we know, for example, that 20 students < 21 students, and the difference between 20 and 21 is the same as the one between 21 and 22. The same applies for the age of your classmates.

Therefore, the age of your classmates and the number of students in a statistics course is an interval data.

You might be interested in

- 7x + 12 - 2x = 23+13x

SpyIntel [72]

Hello, the answer is x=-1/2
Here are the steps....
−7x+12+−2x=23+13x(−7x+−2x)+(12)=13x+23(Combine Like Terms)−9x+12=13x+23−9x+12=13x+23
−9x+12−13x=13x+23−13x−22x+12=23
−22x+12−12=23−12−22x=11
−22x−22‌=‌11−22‌x=‌−12
Hope this helps you!!

6 0

3 years ago

Tim has been trying to lose weight. Through exercise, he was able to lose 5 pounds over 2 weeks. However, Mary lost 10 times as

wolverine [178]

I think 50 pounds. I am not sure.

7 0

3 years ago

Read 2 more answers

Toilet Training You are a great friend and are taking your friend's child to the playground to play with two of his friends: Cha

Brilliant_brown [7]

Answer:

Step-by-step explanation:

Hello!

According to a study regarding the average age of female and male kids to complete toilet training is:

Females:

Average age 32.5 months

The standard deviation of 6.7 months

n= 126

Males:

Average age 35.0 months

The standard deviation of 10.1 months

n= 141

The parameter of study is the difference between the age of females are successfully toilet trained and the average age that males are successfully toilet trained. μf - μm (f= female and m= male)

Assuming that both variables have a normal distribution to choose whether you'll use an unpooled or pooled-t to calculate the confidence interval you have to conduct an F-test for variance homogeneity.

If the variances are equal, then you can usee the pooled-t, but if the variances are different, you have to uses Wlche's approach:

H₀: δ²f = δ²m

H₁: δ²f ≠ δ²m

Since both items b. and c. ask for a 95% CI I'll use the complementary significance level for this test:

α: 0.05

$F= \frac{S^2_f}{S^2_m} * \frac{xSigma^2_f}{Sigma^2_m} ~~~F_{(n_f-1); (n_m-1)}$

$F= \frac{(6.7^2)}{(10.1)^2} *1= 0.44$

Critical values:

$F_{125;140;0.025}= 0.71\\F_{125;140;0.975}= 1.41$

The calculated F value is less than the lower critical value, 0.77, so the decision is to reject the null hypothesis. In other words, there is no significant evidence to conclude the population variances of the age kids are toilet trained to be equal. You should use Welch's approach to construct the Confidence Intervals.

$Df_w= \frac{(\frac{S^2_f}{n_f} + \frac{S^2_m}{n_m} )^2}{\frac{(\frac{S^2_f}{n_f} )^2}{n_f-1} +\frac{(\frac{S^2_m}{n_m} )^2}{n_m-1} }$

$Df_w= \frac{(\frac{6.7^2}{126} + \frac{10.1^2_m}{141} )^2}{\frac{(\frac{126^2}{126} )^2}{126-1} +\frac{(\frac{10.1^2}{141} )^2}{141-1} } = 254.32$

The given interval is:

[0.3627; 4.6073]

Using Welch's approach, the formula for the CI is:

(X[bar]f- X[bar]m) ± $t_{Df_w;1-\alpha /2}$ * $\sqrt{\frac{S^2_f}{n_f} +\frac{S^2_m}{n_m} }$

(X[bar]m- X[bar]f) ± $t_{Df_w;1-\alpha /2}$ * $\sqrt{\frac{S^2_f}{n_f} +\frac{S^2_m}{n_m} }$

As you can see either way you calculate the interval, it is centered in the difference between the two sample means, so you can clear the value of that difference by:

(Upper bond - Lower bond)/2= (4.6073-0.3627)/2= 2.1223

The average age for females is 32.5 months and for males, it is 35 months.

Since the difference between the sample means is positive, we can say that the boys were considered "group 1" and the girls were considered "group 2"

You have a95% confidence that the parameter of interest is included in the given confidence interval.

None of the statements is correct, the interval gives you information about the difference between the average age the kids are toilet trained, that is between the expected ages for the entire population of male and female babies.

This represents a guideline but is not necessarily true to all individuals of the population since some male babies can be toilet trained before that is expected as some female babies can be toiled trained after the average value.

I hope it helps!

6 0

3 years ago

What is the size of the matrix resulting from

Lady bird [3.3K]

Answer:

B. 1×3

Step-by-step explanation:

Given the first matrix as [ 4 -1 0] this is 1×3 (row by column)

The second matrix is [2 1 0 ] which is a 3×3 matrix

[-3 -7 2 ]

[1 -5 2]

Hence the answer matrix will be;

[1×3 ] *[3×3]----------------------cancel the shaded numbers to remain with

[1×3]

8 0

3 years ago

A rectangular floor of area 360 m2 is going to be tiled. Each tile is rectangular, and has an area of 240 cm2. An exact number o

scoray [572]

Answer:

1500

Step-by-step explanation:

The area of the regtangular floor is 360m². The floor is going to be retired with tiles having area of 240cm² . We need to find the number of times . Therefore ,

$\implies 360m^2 = 360 \times 10^4 \ cm^2$

And , the number of tiles required will be ,

$\implies n =\dfrac{Area \ of \ floor}{Area \ of \ a \ tile }\\\\\implies n =\dfrac{ 360 \times 10^4 \ cm^2}{240 cm^2} \\\\\implies \underline{\underline{ n = 1,500 }}$

Hence the required answer is 1500 .

4 0

3 years ago