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yaroslaw [1]
3 years ago
14

A group of campers is going to occupy 6 campsites at a campground. There are 16 campsites from which to choose. In how many ways

can the campsites be​ chosen?
Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0

Answer:

The campsites can be chosen in 5,765,760 different ways.

Step-by-step explanation:

Given that a group of campers is going to occupy 6 campsites at a campground, and there are 16 campsites from which to choose, to determine in how many ways the campsites can be chosen, the following calculation must be performed:

16 x 15 x 14 x 13 x 12 x 11 = X

240 x 182 x 132 = X

240 x 24,024 = X

5,765,760 = X

Therefore, the campsites can be chosen in 5,765,760 different ways.

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Hey you ‼️ yeah I unfortunately need your help again these are hard:(
Helga [31]

Answer:

Step-by-step explanation:

The point of this question is to find out the point where two lines intersect. First we need to get the equation of those lines

Slope of line 1:

(Yb -Ya)/(Xb - Xa) =

(-10 - (-14))/(-1 - (-3)) =

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2

Use that slope to find the Y-intercept of line 1

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Slope of line 2

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Therefore line 2 is

y = -x + 10

Now we have 2 equations to solve for the coordinates x and y

y = 2x - 8

y = -x + 10

Substitute y out in one of the equations

2x - 8 = -x + 10

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4 0
2 years ago
A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0
3 years ago
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