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slava [35]
3 years ago
12

Arrange the steps in the correct order to express cos3x in terms of cosx cos(2x)cos(x)-sin(2x)(x) [1-sin^2(x)]cos(x)-[2sin(x)cos

(x)]sin(x) cos(x)-4sin^2(x)cos(x) 4cos^3(x)-3cos(x) cos(2x+x) cos(x){1-4[1-cos^2(x)]} cos(x)-2sin^2(x)cos(x)-sin^2(x)cos(x) cos(x)[1-4sin^2(x)] cos(x)[-3+4cos^2(x)]
Mathematics
1 answer:
noname [10]3 years ago
4 0

cos(3x) = cos(2x+x)

= cos(2x) cos (x) -sin(2x)sin(x)

=(1-2sin^2(x)) cos(x)-(2 sin(x) cos(x)) sin(x)

= cos x -2sin^2(x) cos(x) -2sin^2(x) cos(x)

= cos(x) - 4 sin^2(x) cos(x)

cos(x)(1-4sin^2(x))

=cos(x(1-4(1-cos^2(x))

=cos(x)(1-4+4cos^2(x))

= cos(x)-4cos(x)+4cos^3(x)

=-3cos(x)+4cos^3(x)

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Answer:

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Step-by-step explanation:

< less than

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2 years ago
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Temka [501]

Answer:

y= 2x -3

Step-by-step explanation:

Let's rewrite the given equation into the form of y=mx+c, so that we can find the gradient of the line. In this form, m (coefficient of x) is the gradient.

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5 0
3 years ago
Find the zero of the following function: f(×)=(×-1)/(×-3)​
nlexa [21]

Answer:

\boxed{\sf \ \ x = 1 \ \ }

Step-by-step explanation:

Hello,

First of all we need to take x different from 3 as dividing by 0 is not allowed

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f(x)=0\\\\ \dfrac{x-1}{x-3}=0\\\\ x-1 = 0\\\\ x = 1

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Leviafan [203]

Answer:

7

Step-by-step explanation:

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f(x2) - f(x1)

--------------------

x2-x1

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