Question

On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above and to the left of the line is shaded.
Which linear inequality is represented by the graph?

y ≤ One-thirdx − 1
y ≥ One-thirdx − 1
y < 3x − 1
y > 3x − 1

Answer 1

Answer: C

Step-by-step explanation:

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Answer 2

Answer:

Option B.

Step-by-step explanation:

A solid straight line passes through (0, -1) and (3, 0)

Slope of the line = $\frac{y-y'}{x-x'}$

= $\frac{0+1}{3-0}$

= $\frac{1}{3}$

Equation of the line passing through (0, -1) will be  

y - y' = m(x - x')

$y+1=\frac{1}{3}(x-0)$

$y=\frac{1}{3}x-1$

Since this line is solid then there will the sign of (≥ or ≤)

If everything above and to the left of the line is shaded then the inequality will be

$y\geq \frac{1}{3}x-1$

Therefore, the answer will be option B. $y\geq \frac{1}{3}x-1$