AK = 640
Δ ABC and ΔFJK are similar. They are small triangles.
ΔCDF is the big triangle.
640 / 2 = 320 m= CF
AC & FK= 320/2 = 160 m each
2AC = CF = 2FK
2(160) = 320 = 2(160)
BG = 20 m
20/160 = x / 320
20*320 = 160x
6400 = 160x
6400/160 = x
40 = x
Area of CDF = (40 m * 320 m)/2 = 12,800 / 2= 6,400 m²
An exterior angle is equal to the sum of the 2 non adjacent angles. In this case
100 = x + 70 Subtract 70
x = 100 - 70
x = 30
To do this problem you would first need to factor out a variable, which in this case I would want to do the first equation because it is isolated. Now the equations would look like this:
x = -2y - 1
4x - 4y = 20
Since we know that x is now equal to -2y - 1 we can plug it in to the x value in the second equation:
4 (-2y -1) - 4y = 20
-8y -4 - 4y
-12y - 4 = 20
-12y = 24
y = -2
Now that we know the y value plug the y value to one equation to find the x, I will be using the first equation
x + 2(-2) = -1
x - 4 = -1
x = 3
Solutions:
y = -2
x = 3
Answer:
150 scores
Step-by-step explanation:
The computation of the score did she get is shown below:
Since there is 18 test presented
And if the test is done on correct manner so 10 points should be awarded
Now since fifth-sixth would be done correctly
So,
= 18 × 5 ÷ 6 × 10
= 150 scores
The answer would be 1.0404 because 1.02 multiplied by 1.02 is 1.0404
