I'm pretty sure it's 50°f because the original temperature is 37°f and after 8 minutes it was 42°f and 42 minus 37 is 5, 8 divided by 5 is 1.6 and then multiply that by 5 is 8 and 42 + 8=50°F
Answer:
Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla
Step-by-step explanation:
we know that
The area of a circle is equal to
where
r is the radius
step 1
Find the area of the 10 inch-round quesadilla
we have
substitute
step 2
Find the area of the 5 inch-round quesadilla
we have
substitute
step 3
Which is larger, half of the 10-inch quesadilla or the entire 5-inch quesadilla?
Compare
half of the 10-inch quesadilla is equal to ----> 
the entire 5-inch quesadilla ---->
therefore
Half of the 10-inch quesadilla is greater than the entire 5-inch quesadilla
Subtract the cost of tickets from the total. 4x7.5=30. 58-30=28. Eight boxes of candy were purchased in total. Use c to represent candy. 8c=28. Finally, divide both by 8. 28/8= 3.5. The answer is $3.50.
The ? Is 11.
You add the equations to get rid of one variable, then you have 6x=24 then you divide both sides and you have x=4, then you substitute the given value of x and you are left with 5*4 - y = 9. And the solution or well possible solution is y = 11 which gives youuuuu. (x , y) = (4 , 11)
P = 2(L + W)
510 = 2(L + W) ...divide both sides by 2
510/2 = L + W
255 = L + W
3/5(255) = 765/5 = 153 cm <== length
2/5(255) = 510/5 = 102 cm <== width
