Answer:
y ≠ 9, y ≠ 3
Step-by-step explanation:
y² -12y +27 = (y - 9) (y - 3)
Denominator ≠ 0
y ≠ 9 or y ≠ 3
<span>g(x) = x^2 + 3x - 4 (please be sure to use " ^ " to denote exponentiation).
This function factors into g(x) = (x+4)(x-1), and so the zeros are -4 and +1.
If we shift this graph 5 units to the left, we get h(x) = (x+5)^2 + 3(x+5) - 4.
The new zeros will be -4-5 and 1-5, or -9 and -4.
</span>
Answer:
That’s correct
Step-by-step explanation:
Answer:3
Step-by-step explanation:
8x3+1=25
25÷25/3
25×3/25
=3
