Answer:
5,000
Step-by-step explanation:
5,000 x .05 = 250
250 + 1,250 = 1,500
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
Distribute it out. you should end up with (y^2+7y) + (5y+35) add the 7y and the 5y to get 12y. you will have y^2+12y+35. tbh i have no idea what to do from there. its been so long since i have studied this
Answer:
9 times
Step-by-step explanation:
397/45= 8.6 Round to nine because you cant have half rides
Answer:

Step-by-step explanation:
<u><em>The complete question is</em></u>
Suppose that a new fuel-efficient European car travels an average of 28 kilometers on 1 liter of gasoline. If gasoline costs 1.50 euros per liter, how much will it cost to drive 220 kilometers ?
step 1
using proportion
Find out the number of liters of gasoline needed for 220 kilometers
so

step 2
Find the cost to drive 220 kilometers
Multiply the cost of one liter of gasoline by the total liters of gasoline needed to travel 220 Km
so
