Answer:
$85
Step-by-step explanation:
5000 x $70 = $350,000
4950 x $71 = $351,450
4900 x $72 = $352,800
etc.
Create an equation for the monthly revenue:
f(n) = (5000 - 50n) x (70 + n)
= 350000 + 5000n - 3500n - 50n²
= 350000 + 1500n - 50n²
where n is the amount the ticket price is increased from $70.
Differentiate, equal to zero and solve for n to find the value of n when the monthly revenue is at its maximum:
f'(n) = 1500 - 100n
1500 - 100n = 0
1500 = 100n
15 = n
Therefore, the maximum monthly revenue is when n = 15.
So the cost of the ticket will be 70 + n = 70 + 15 = 85
$50 each.................... hope it helped
The easiest way to find that answer is to look at the solution that I just gave you for the same ball traveling at 30 M/Sec, and just substitute 20 in place of 30 in that solution.
Answer:
Yes, No, Yes, No, No
Step-by-step explanation:
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