n(A-B) denotes elements which are in A but not in B
n(Au B) denotes elements in A and B
n(AnB) denotes elements that are common in A and B
Now I will add one more set
n(B-A) which denotes elements in B but not in A
So, n(AuB) = n(A-B) + n( B-A) +n(AnB)
70 = 18 +n(B-A) + 25
70 = 43 + n(B-A)
n(B-A) = 70-43
n(B-A) = 27
So, n(B) = n( B-A) + n( AnB)
= 27+25
= 52
Answer:
o
Step-by-step explanation:
o
9514 1404 393
Answer:
(0, 2), (5, 5)
Step-by-step explanation:
The w-intercept is the constant in the equation, so you know immediately that (x, w) = (0, 2) is one point on your graph.
Since the value of x is being multiplied by 3/5, it is convenient to choose an x-value that is a multiple of 5. When x=5, we have ...
w(5) = (3/5)(5) +2 = 3+2 = 5
So, (x, w) = (5, 5) is another point on your graph.
?????? Is there a picture? I can’t see it if there is :)