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barxatty [35]
3 years ago
11

Which statement is correct? StartFraction 1 inch Over 2.54 centimeters EndFraction = StartFraction 7 inches Over 17.68 centimete

rs EndFraction StartFraction 1 foot Over 12 inches EndFraction = StartFraction 7 feet Over 74 inches EndFraction StartFraction 1 yard Over 36 inches EndFraction = StartFraction 7 yards Over 252 inches EndFraction StartFraction 1 meter Over 3.28 feet EndFraction = StartFraction 7 meters Over 22.86 feet EndFraction
Mathematics
2 answers:
kumpel [21]3 years ago
5 0

Answer:

1 yard Over 36 inches

hope this helps

Arte-miy333 [17]3 years ago
3 0

Answer:

1 yard Over 36 inches EndFraction = StartFraction 7 yards Over 252 inches

Step-by-step explanation:

b/c i just know

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Diano4ka-milaya [45]

5s + 5l = 155, 10s + 12l = 346

Solve for s in the first equation.

5s = 155 - 5l

s = 31 - l

Substitute s into the second equation.

10(31 - l) + 12l = 346

310 - 10l + 12l = 346

310 + 2l = 346

2l = 36

l = 18

Substitute l into the first equation.

5s + 5(18) = 155

5s + 90 = 155

5s = 65

s = 13

s = 13, l = 18

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Is there a proportional relationship between x and y?
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Answer:

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3 years ago
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Answer:?

Step-by-step explanation:

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And wins a metal in the shape of a circle for finishing a marathon which statements about the metals are true use 3.14 for pi. S
PilotLPTM [1.2K]

Answer:

The true statements are:

C. If the metal has a radius of 2.5 inches then it has an area of 19.625 in.²

D. If the metal has a diameter of 3 inches and it has a circumference of 9.42 inches.

E. If the metal has a circumference of four pi inches then it has an area of four pi square inches

Step-by-step explanation:

Let us revise the rule of circumference and area of a circle

  • The formula of the circumference of a circle is <em>C = π d</em>, where d is the diameter of the circle OR <em>C = 2πr</em>, where r is the radius of the circle
  • The formula of the area of a circle is <em>A = πr²</em>
  • The radius of a circle is equal to half its diameter

A.

∵ The metal has a circumference of 7π inches

∵ C = 2πr

- Equate πd by 7π

∴ πd = 7π

- Divide both sides by π

∴ d = 7 inches not 3.5 inches

∴ A is not true

B.

∵ The metal has a circumference of 3π inches

∵ C = 2πr

- Equate 2πr by 3π

∴ 2πr = 3π

- Divide both sides by π

∴ 2r = 3

- Divide both sides by 2

∴ r = 1.5 inches

∵ A = πr²

∴ A = π(1.5)²

∴ A = 2.25π inches² not 9π inches²

∴ B is not true

C.

∵ The metal has a radius of 2.5 inches

∴ r = 2.5

∵ A = πr²

∵ π = 3.14

∴ A = 3.14(2.5)²

∴ A = 19.625 inches²

∴ If the metal has a radius of 2.5 inches, then its area is 19.625 in.²

∴ C is true

D.

∵ The metal has a diameter of 3 inches

∴ d = 3

∵ C = πd

∵ π = 3.14

∴ C = 3.14(3)

∴ C = 9.42 inches

∴ If the metal has a diameter of 3 inches, then its circumference

  is 9.42 inches

∴ D is true

E.

∵ The metal has a circumference of 4π inches

∵ C = 2πr

- Equate 2πr by 4π

∴ 2πr = 4π

- Divide both sides by 2π

∴ r = 2

- Now you can find the area

∵ A = πr²

∴ A = π(2)²

∴ A = 4π

∴ If the metal has a circumference of 4π inches, then its area

   is 4π  inches²

∴ E is true

The true statements are:

C. If the metal has a radius of 2.5 inches then it has an area of 19.625 in.²

D. If the metal has a diameter of 3 inches and it has a circumference of 9.42 inches.

E. If the metal has a circumference of four pi inches then it has an area of four pi square inches

8 0
3 years ago
Jaime has 5 over 11 spaceof a project completed while Tim has finished 7 over 13 spaceof the same project.
faust18 [17]

Answer:

a. Tim has completed a greater amount of work.

b. Together they have completed \frac{142}{143} part of two projects.

Step-by-step explanation:

Let us assume that the project on which Jaime and Tim are working has x amount of space.

Now, given that Jaime has 5 over 11 space of a project completed while Tim has finished 7 over 13 space of the same project.

Therefore, Jaime has completed \frac{5x}{11} amount of space and Tim has finished \frac{7x}{13} amount of space.

a. Now, (7x) \times 11 > (5x) \times 13

⇒ \frac{7x}{13} > \frac{5x}{11}

Therefore, Tim has completed the greater amount of work. (Answer)

b. Together they have completed (\frac{7x}{13} + \frac{5x}{11}) = \frac{(7 \times 11 + 5 \times 13)}{13 \times 11} x = \frac{142}{143}x amount of space out of 2x amount of space. (Answer)

4 0
3 years ago
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