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stich3 [128]
3 years ago
14

The width of a rectangle is 2 less than its length. If the perimeter of the rectangle is no more than30 centimeters, find the ra

nge of possible lengths and widths of the rectangle. Use the formula, P=2L+2W, for the perimeter of the rectangle.
Mathematics
1 answer:
arlik [135]3 years ago
4 0
If this is what u are asking for 240 is what i got for the answer
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Simplify completely quantity x squared plus 4 x minus 45 all over x squared plus 10 x plus 9 and find the restrictions on the va
Brums [2.3K]

Answer:

A) Quantity x minus 5 over quantity x plus 1, where x≠-1 and x≠-9

Step-by-step explanation:

\frac{x^2 + 4x - 45}{x^2 + 10x + 9}

Simplifying the numerator first:

x² + 4x - 45 using the quadratic formula you get;

(x - 5)(x + 9)

Then simplifying the denominator x² + 10x + 9 using a quadratic formula you get;

(x + 1)(x + 9)

Dividing the numerator and denominator now gives;

\frac{(x - 5)(x + 9)}{(x + 1)(x + 9)}

Cancelling (x + 9) throughout leaves you with;

\frac{x - 5}{x + 1}

The only restrictions here is if x = 1 and 9 which will give an undefined answer.

7 0
3 years ago
Read 2 more answers
What is the area of the figure?<br><br><br>○ 45 cm²<br>○50 cm²<br>○70 cm²<br>○90 cm²​
anyanavicka [17]

Answer:

third option; 70 cm²

Step-by-step explanation:

<u>Rectangle:</u>

5 x 10 = 50

<u>Triangle:</u>

1/2bh

18 - 10 = 8

1/2 5(8)

1/2 40

20

<u>Total area:</u>

50 + 20 = 70 cm²

5 0
2 years ago
Read 2 more answers
Find two numbers that may be rounded and added together to make 50
adell [148]
25 + 25 <<<<< I think .
3 0
2 years ago
Atriangle was translated 4 units down.
loris [4]

Answer:

Idk if this is right but I think it's The transformed shaped shifted 7 units to the right so add 7 to x and it shifted 6 units down so subtract 6 from y.

The answer is (x,y) = (x+7) (y-6)

Hope this helps!!!?

7 0
3 years ago
Read 2 more answers
What is the interquartile range of this data 0 5 10 15 20​
timama [110]
The interquartile range (IQR) is 15.

To find the IQR, you must:
1) Find the median
2) Split the data set in two at the median.
3) Find the medians from both the groups you made in Step 2
4) Label the smaller one Quartile 1 and the larger one Quartile 3 (Hint: The median is Quartile 2)
5) Subtract: Quartile 3 - Quartile 1
5 0
3 years ago
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