Question

Write an equation of a line that passes thought he point (-5,2) And is parallel to the line represent by the equation 2x + 5y = 15

Answer 1

Answer:

The parallel line would be y = -2/5x + 4

Step-by-step explanation:

In order to find this, we can first note that the new line would have the same slope since parallel lines share slope. To find that, we need to solve the first equation for y =.

2x + 5y = 15

5y = -2x + 15

y = -2/5 + 3

So, with a -2/5 slope, we now can find the intercept by using the point.

y = mx + b

2 = -2/5(-5) + b

2 = -2 + b

4 = b

Now with the slope and intercept found, we can model the equation.

y = -2/5x + 4