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3 years ago

12

The area of a rectangle is 35 ft2 , and the length of the rectangle is 8 ft less than three times the width. find the dimensions

of the rectangle.

1 answer:

atroni [7]3 years ago

8 0

The width is five feet and the length is seven feet.

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A strip of wood 78 inches long is to be cut into pieces 3 3/4 inches long. How many pieces can be cut?. . A. 12. B. 26. C. 20. D

mafiozo [28]

20 A strip of wood 78 inches long can be cut into 20 3 3/4 inch pieces. (78/3.75 = 20.8 Since you can't have a .8 piece of wood, the answer is 20)

6 0

3 years ago

Read 2 more answers

12 over 12 and blank over 20

erastova [34]

Answer:

12/12=20/20

Step-by-step explanation:

if the original question deals with fractions, then 12 over 12 is the same as 20 over 20 because they both reduce to 1

6 0

3 years ago

For f(x)=1/x^2-3

igomit [66]

For f(x)=1/x^2-3

Find

A) f(3)

B) f(2-h)

If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9

If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:

1

f(2-h) = ------------------ - 3

4-4h +h^2

5 0

3 years ago

What is an equation of a line which passes through (6,9) and is perpendicular to the line whose equation is 4x − 6y = 15?

Svetllana [295]

<u>Given:</u>

The equation of the line passes through the point (6,9) and is perpendicular to the line whose equation is $4 x-6 y=15$

We need to determine the equation of the line.

<u>Slope</u>:

Let us convert the equation to slope - intercept form.

$-6 y=15-4x$

$y=\frac{2}{3}x-\frac{5}{2}$

From the above equation, the slope is $m_1=\frac{2}{3}$

Since, the lines are perpendicular, the slope of the line can be determined using the formula,

$m_1 \cdot m_2=-1$

$\frac{2}{3} \cdot m_2=-1$

$m_2=-\frac{3}{2}$

Therefore, the slope of the equation is $m=-\frac{3}{2}$

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting the point (6,9) and the slope $m=-\frac{3}{2}$ in the above formula, we get;

$y-9=-\frac{3}{2}(x-6)$

Simplifying the terms, we get;

$2(y-9)=-3(x-6)$

$2y-18=-3x+18$

$3x+2y=36$

Thus, the equation of the line is $3x+2y=36$

3 0

3 years ago

Please help!!<br> Find the zeros and vertex of the parabola

Sergeeva-Olga [200]

Answer:

Vertex: (1/2, 16)

Zeros: t = − 1 /2, 3/2

Step-by-step explanation:

4 0

3 years ago