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agasfer [191]
3 years ago
11

How to find empirical formula

Chemistry
2 answers:
Gnesinka [82]3 years ago
8 0
The best way to calculate the Empirical Formula of a compound which I assume is what you're asking, is by steps:
1)Assume that you have 100 g of the unknown compound.
2)Convert the masses from Step 1 into moles using the molar mass.
3)Determine which element has the smallest mole value. Then divide all the mole values you calculated in Step 2 by this smallest value.
4)If any of your mole ratios aren’t whole numbers, multiply all numbers by the smallest possible factor that produces whole-number mole ratios for all the elements.
5)Write the empirical formula by attaching these whole-number mole ratios as subscripts to the chemical symbol of each element.
Fittoniya [83]3 years ago
6 0
Here's how to find an empirical formula when given percent composition:<span>Assume that you have 100 g of the unknown compound. ...Convert the masses from Step 1 into moles using the molar mass.<span>Determine which element has the smallest mole value.</span></span>

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4 years ago
If 309 grams of potassium combines with 228 g chlorine gas, how many grams of the single product will be formed? What are the LR
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The amount of KCl that would be formed will be 478.8 grams

<h3>Stoichiometric calculations</h3>

From the equation of the reaction, the mole ratio of K to Cl_2 is 2:1.

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More on stoichiometric calculations can be found here: brainly.com/question/27287858

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4 0
2 years ago
URGENT HELP NEEDED
balu736 [363]
<span>the balanced equation for the reaction is as follows
2C</span>₄H₁₀ + 13O₂ ---> 8 CO₂ + 10H₂<span>O
 stoichiometry of C</span>₄H₁₀ to O₂ <span>is 2:13
stoichiometry applies to the molar ratio of reactants and products. Avagadros law states that volume of gas is directly proportional to number of moles of gas when pressure and temperature are constant.
 Therefore volume ratio of reactants is equal to molar ratio, volume ratio of C</span>₄H₁₀ to O₂<span> is 2:13
 2 L of </span>C₄H₁₀ reacts with 13 L of O₂<span> 
then 100 L of </span>C₄H₁₀<span> reacts with 13/2 x 100 = 650 L
 therefore 650 L of O</span>₂<span> are required </span>
7 0
3 years ago
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